Similarity ( As a size Transformation) | Class 10th Math Chapter 15 | R.S.Aggarwal Math | ICSE MATH

Brief Summary

This video provides an introduction to similarity and size transformation in geometry. It covers the basic concepts of similar figures, enlargement, and reduction, and explains how to apply scale factors to find the dimensions and areas of transformed figures. The video includes step-by-step solutions to various problems, illustrating how to use formulas and scale factors in different scenarios, such as maps and models.

  • Similar figures maintain the same shape but can differ in size.
  • Size transformation involves enlargement (increasing size) or reduction (decreasing size).
  • Scale factors are used to determine the ratio between corresponding sides of similar figures.
  • Formulas are applied to calculate resulting lengths, areas, and volumes after size transformations.

Introduction to Similarity and Size Transformation

The chapter focuses on similarity as a size transformation, building upon previous concepts. Similarity in figures means they have the same shape, but their sizes can differ. For example, two triangles with proportional sides (e.g., 2:4, 3:6, 4:8) are similar. Similarly, circles of different radii are also similar because they share the same shape.

Similarity as a Size Transformation

Size transformation involves changing the size of a figure, either by enlargement (making it bigger) or reduction (making it smaller). Enlargement increases the size, while reduction decreases it. In size transformation, the original figure is the "object," and the transformed figure is the "image." Formulas are used to relate the resulting figure to the given figure using a scale factor (k).

Formulas and Scale Factor

The resulting figure is obtained by multiplying the given figure by a scale factor (k). For length, the formula is: Resulting Length = k * Given Length. For area, it is: Resulting Area = k^2 * Given Area. For volume, it is: Resulting Volume = k^3 * Given Volume. If k > 1, it's an enlargement; if k = 1, it's an identity transformation (no change); if k < 1, it's a reduction. In models and maps, the scale factor is often given as a ratio (e.g., 1:25000).

Question 1: Finding Sides of a Similar Triangle

Given a triangle ABC with sides 3.6 cm, 4.5 cm, and 6 cm, a similar triangle A'B'C' is created with the largest side (A'C') being 10 cm. The scale factor is found by dividing the new largest side by the old one (10/6 = 5/3). The lengths of the other sides of the new triangle are then calculated using this scale factor: A'B' = (5/3) * 3.6 = 6 cm and B'C' = (5/3) * 4.5 = 7.5 cm.

Question 2: Reduction of a Triangle

A triangle ABC has sides 16 cm, 12 cm, and 18 cm. A similar, smaller triangle A'B'C' is created such that the smallest side is 4.8 cm. The scale factor is calculated as 4.8/12 = 2/5. The lengths of the other sides of the reduced triangle are then found: A'C' = (2/5) * 16 = 6.4 cm and A'B' = (2/5) * 18 = 7.2 cm.

Question 3: Area of an Image After Reduction

A triangle has its size reduced by a scale factor of 0.72. If the original area of the triangle is 62.5 cm^2, the area of the image is calculated using the formula: Area of Image = k^2 * Given Area = (0.72)^2 * 62.5 = 32.4 cm^2.

Question 4: Finding the Scale Factor of Enlargement

A rectangle with an area of 60 cm^2 is enlarged. The area of the resulting image is 135 cm^2. To find the scale factor, the formula Area of Image = k^2 * Given Area is used. Thus, 135 = k^2 * 60, which gives k^2 = 135/60 = 9/4. Therefore, the scale factor k = √(9/4) = 3/2 = 1.5.

Question 5: Map Scales and Actual Lengths

On a map with a scale of 1:25000, a triangular plot has sides of 6 cm and 8 cm, with one angle being 90 degrees. Using the Pythagorean theorem, the third side is found to be 10 cm. The actual lengths of the sides are calculated using the scale. For the 8 cm side: Actual Length = 8 * 25000 cm = 2 km. For the 10 cm side: Actual Length = 10 * 25000 cm = 2.5 km. The area of the image is (1/2) * 8 * 6 = 24 cm^2. The actual area of the plot is then calculated, converting the map scale to square kilometers.

Question 6: Area Representation on a Map

The scale of a map is 1:200,000. The length on the ground represented by 1 cm on the map is calculated as 1 cm * 200,000 = 2 km. An area of 3 cm^2 on the map represents an actual area of 12 km^2 on the ground. The area on the map representing a 10 km^2 plot of land is calculated using the scale factor, resulting in 2.5 cm^2.

Question 7: Diagonal Distance on a Map

On a map with a scale of 1:200,000, a rectangular plot measures 32 cm by 24 cm. The diagonal distance on the map is found using the Pythagorean theorem to be 40 cm. The actual diagonal distance is calculated as 40 cm * 200,000 = 8 km. The actual area of the plot is calculated as 3.072 km^2.

Question 8: Dimensions and Volume of a Multi-Story Building Model

The dimensions of a multi-story building model are given, and the scale is 1/60. The actual dimensions are calculated: 1 meter * 60 = 60 meters, 60 cm * 60 = 36 meters, and 1.25 meters * 60 = 75 meters. The floor area of a room in the model is 250 cm^2, and the actual area is calculated as 90 m^2. The volume of a room in the model is related to the actual volume of 648 cubic meters, and the model volume is found to be 3000 cm^3.

Question 9: Ship Model Length, Area and Volume

A ship model is made to a scale of 1:250. If the length of the model is 1.2 meters, the actual length of the ship is 300 meters. If the area of the deck of the model is 1.6 m^2, the actual area of the ship's deck is 100,000 m^2. If the volume of the model is related to an actual volume of 1 km^3, the volume of the model is 64 m^3.

Question 10: Ship Model Dimensions and Volume

The length of a ship model is 4 meters, and the scale is 1:200. The actual length of the ship is 800 meters. If the area of the deck of the ship is 160,000 m^2, the area of the model's deck is 4 m^2. If the volume of the model is 200 liters, the actual volume of the ship is 16,000,000 m^3.

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Transcript

Full transcript of “Similarity ( As a size Transformation) | Class 10th Math Chapter 15 | R.S.Aggarwal Math | ICSE MATH”. Click a timestamp to open the video at that moment. Need another video? Use the YouTube transcript generator.

0:00 Hello students, welcome to all of you now to your own youtube1 Previously we had done 16th I am doing 15 because it relates to 16 brother, okay, the things that we have learnt in both of them in the previous chapter, today we will start the chapter, there is similarity in both of them brother, okay and what is the name of this chapter also brother, our similarity as a size transformation, so before doing this chapter, we will learn a little bit of its basic introduction, the basic introduction is very important, the one who knows about it will be able to do the chapter easily, it is just one exercise, our chapter will be over quickly, this is okay brother, so listen carefully brother, what am I saying in its introduction, first of all let's talk about similarity, the similarity of a figure, when will we call any figure similar, listen carefully, when will we call any figure similar, suppose you have a triangle like this and a

0:46 triangle like this, can I call these figures similar, yes brother they are similar, how? It is similar, listen to that carefully now suppose its side is 2 3 4, suppose its 4 6 8, so look, double of two, double of three and double of four is the size of our shape, which is actually double of this, okay. And at the same time, what is there here, both the figures are same, both have three sides, three vertices, three angles, okay, so what will our figure be called in this, it is called similar, the size of the figure can be small or big but the shape should be the same, look at its shape, it is triangular, its also is triangular, so the shape should be the same, for example, take a circle and a bigger circle, these will also be similar because the shape of both of them is the same, whether the radius is small or big, there will be no difference in it, okay, I

1:33 understand what are similar figures, those whose sides are equal, whose figure looks similar, okay, so we can call them similar, whether the angles are equal or those will also come in similar, okay, let's do it next brother. Topic Similarity as a Size Transformation Now here similarity is okay, what do you mean by saying that we have to transform the size, suppose you have a small triangle, this size has to be transformed, so it means you have to make it bigger, what do you have to do, transform its size, make the size bigger or make this from this triangle, make the size smaller, it is your choice, okay, we will give you that in the question, whenever you get the statement, you will know in it, inside the statement, its enlargement pic, ours, the

2:21 size is getting bigger due to enlargement, this is called enlargement, increasing the size is given in similarity figures, so we have to make it bigger, okay and next comes up here small, that means we have to reduce it, make it smaller from bigger, so this is called reduction, this is called reduction, when you make a very small triangle from a big triangle, then what is it called, it is called reduction, okay, next comes size transformation, there are two things, first we have the object, that is, your You have a triangle, given this is your object and by changing it you are making a new triangle, what are you making, you are making a new triangle which is bigger, under which does it come, it comes in which part of your image, it will come inside the image, listen carefully, it is an object, its size is small, okay and when you enlarge it, what

3:07 you are getting here, the map or whatever model is there, then what will it be called, here it is called image, this thing was now let's go a little towards the formula, brother, look carefully at the formula which we will use, suppose you have a resulting figure, what have you given, you have given a resulting figure, how have you extracted it, we have extracted it by multiplying it by its ratio, whatever you will get, there is scale and into the given figure, whatever your given figure will be, okay, we have multiplied the given figure by some ratio and enlarged it, so you get the resulting figure, similarly with your figure in area, now this was the length, area can also be k scale and area We will multiply the given by this, what will happen in volume, it will become k3 and we will multiply the given volume and now let's talk about the scale here, our k, if the value of k is greater than one, then

3:53 it means it comes under enlargement, which we have just read, the topic is here, look, if you are taking the value of k to be large, here the ratio is greater than one, then it comes under enlargement, the value of k is equal to 2, then it comes in your case, brother, here it will come in identity, that means it will neither be large nor small, it will remain the same figure, we will call it identity transformation, this is okay and next, brother, if the value of k is less than one or smaller, then it comes in reduction, that means where you have to take it smaller than one, that means reduce the shape a little and so it comes in reduction, now let's talk about the model here, the same formula will work in the model, your scale factor is 1 ba p, that means the value of k is 1 p for you. You will find it in the question like 1 Ba 25000 has been given, there is a question, I think this is 1 Ba 25000 in the book, so the value you have in it would be 1 Ba 25000,

4:41 so you have to solve the question using that, we will talk about that when we ask the question and similarly there is a map, similar formulas would have been given to you in the map that the resulting map length of the resulting map equal to k into me actual length of the map, okay, it would have been given like this, you will use these formulas only, so this was a little basic introduction that we did, now let's start the exercise, after this let's start the exercise, brother, before starting the exercise, the children who have not yet subscribed to the channel, brother, subscribe to the channel, share the video with your friends and classmates as well, brother, so that they can also be helped, see brother, the first question has asked you that your triangle is such in which you have given the sides, so first let me draw a triangle, I will keep the name here for you Its a b c in which a has been given to you any amount i.e. 3.6, okay, b c has been given to you 4.5 and c has been given to you 6 cm, okay,

5:30 these things have been given to you a here after that you have to make a new triangle whose name is a' bead c d so here you have to make a new triangle brother whose sides will be a little n larger, so a d bead and c d now what has been said that the largest side of the largest triangle, see brother which is the largest side in this is a so in this also there will be adds d larger, how much has been given of 10 cm, write down all the sides of 10 cm then you will get any one side of it now which one has been given 10, this one find the scale factor, so first of all we find the scale factor, what do we find, brother first of all the scale factor is equal to what, ai which is the given largest side in divide and in this side which is equal to what, look here is a d so divide ch here

6:17 brother 2 * 5 10 2 * 3 6 So what is the scale factor brother 5/3 is the scale factor, we have found out the scale factor now let's find the second thing use it to now you have to use this scale factor and find the length of the other side and which other side do you have to find out a'b' look brother I am finding the length of a'b' so first of all you have to write 5/3 what is the actual length of a'b' in scale factor multiply that means what is 3.6 of a now remove the 3.6 point, 10 will be below brother now subtract 5 from 5 * 2 10 okay and subtract this 3 * 1 3 3 * 2 6 subtract six from two so the answer will be how much will be six brother whose actual length will be in 6 cm brother of our ad bead now let's find out the length

7:02 of length of which one is left brother bead seed length of bead seed so write the same scale factor 5/3 into me it's very simple The question is now what is the length of the bead 4.5 so if you remove the point then how much is left in 4.5 by 10 cut 5 from 5 cut 3 from 3 and 3 3 5 15 if you cut from u then it means 7.5 cm. Here brother we have done the questions that we had to do here, we have also found out the actual length that we had to find out, see it is very simple, let's move on to the next one, that is also the same. First you have a triangle which is given as ABC, make it same to same, suppose I have made a triangle whose name is ABC after that what did I say, that the smallest side of the triangle is 4.8

7:49 cm. Now let's write down its first side, brother how much is the side of A, brother 16, after that BC is 12, after that C is 18 18, okay brother how much is the side of C, 18 16 18 12, this value is given. Now here we have to make this the smallest triangle, that means what we have to do with it is reduction, what did we do here, enlargement, here we are doing reduction, making the reduction smaller, whose name is the same, keep a d, b d and c d, okay, clear, now what will we do here, now see whose is 4.8, read it carefully here, the truth is that the smallest side of the triangle, see which is the smallest, this is 12, so which side will be the smallest, 4.8 how much will it be 4.8, after that find the scale factor, so like before, just like we

8:37 found the scale factor here, write it, what will be the scale factor here, write the scale, 4.8 is given in divide, in its divide, this side is 12, so remove the point g below, how much will it be, brother, how much will 10 be, 10 then it is 12 4 48, 12 * 4 48 2 * 2 4 2 * 5 10, so what was the answer 2/5 scale factor How much did your 2/5 come out to be? Okay now what do you have to find out, use it and find the length of the other side. Find the length of the other sides. So, I will find out the length of an ad seed. So, write the length of an ad seed. So, what is the formula? First, write the scale factor, brother. 2 2/5 in multiply. See here, what is the length of an ad seed? 16. So, 16 2 32 b

9:25 5. Convert this into points. 5 6 30 5 * 4 10 20. So, it comes out to be 6.4 cm. Okay, find out the length of the ad seed. Length of an ad seed. So, brother, find the scale factor into it and what was its length? 18 18 d 36 by 3, how much did you subtract from 5 by 35. So, 5 t 10 = 7.2 cm. So, what is this, here, the length of an ad seed. Here, we have completed it. So, our question number, which is second, is complete. It is done, both the questions are done in exactly the same way, it is very easy, you can do it easily, let's do the next one brother, question number third, see what have I told you in the third, here there is a triangle pakka which has been

10:11 reduced according to a scale, its value is 0.72, you know what I used to consider the scale, here I take the value of 0.72 brother, okay if the area of the triangle pakka is this, find the area of an image, to find out the area of the image, what was our formula, A of an image equal to ke square, you know ke square area into me area of given triangle pakka, so what would be the area of the image, we will keep it the same, we will write this, this area of an image is your 0.72 0.72 square into me

10:56 actual what is our given area, what is its area, write 62.5, 62.5 so while solving this, look at this, 0.72 will have to be done twice because above We will have to multiply it and into 62.5. Okay brother, remove its point. Take this from this. I remove the point below. 100 will be required. I remove its point as well. How much will it be below? 100. I remove its point below. How much will it be below. 10 now let us subtract this on the table of 25. Okay, 25 becomes 100 brother. And 25 to 50, how much is left? 12 25 5. This becomes then back to 25 4 100. Now subtract this by four. Divide this also by four, how much will be left? 4 one 4 is left here, how much brother? Three

11:42 4 8 32. Divide this again by four. 18 18 and how much is 18, brother? 324 324 by one 10 is left below. So the answer will be 32.4 cm square. So how much area of the image did you get, 32.4 cm square. You had to solve it in this manner. Next, see, there is a rectangle whose area is given to you as 60 cm. Okay, transform under the Enlargement about the point in space if the area of and its image, judge the area of this image is given to us, then we have to find the scale factor, so what will we do for this, apply the same formula, area of an image is equal to area, so we will write k scale into me, brother, area of the given figure, whatever is the area of the given figure, whatever is

12:32 given, okay, how much area of the image have we given, look here, the area of the image is given, write 135, 135 k scale as it is because that has to be found, and how much of the given figure do we have 60, brother, 60 60 multiply and divide, so what will be the value of k scale, 135 in 60, let's cut it from the table of 15, 15 4 60 9, we have 135 k scale, whose square is 3, whose square is four, whose square is 2, so the whole square of 3/2 comes, brother, if the square is cut from the square, then the value of k will be 3/2 If you cut it, it would be 1.5 cm. So your final k was, brother, sorry do not write centimeters. Here, your given factor was how much, 1.5.

13:19 We had to find the scale factor here. Here, find the scale factor of enlargement, how much was it, 1.5. So it is greater than one, right? k, so it means it is in enlargement. And what was here, it was smaller than one, 0.72. So what was this, it was in reduction in the beginning, that is why it was written reduced here. Okay brother, so question number four is done. Let's do the next one. Let's do question number fifth. Brother, in the fifth, see what is given to you, here on a map drawn to a scale of this, you have been given a scale of 1 2000, where there is a triangular plot, we take a triangular plot, here I make a triangle, its name is A A A and the A is of how many degrees, 90 degrees, I will make 90 here, after that what is the value of m A, bha here the value of A A How much 8 is given here and what is the value of L,

14:05 Bha, here the value of L and m is given as 6. So first of all, let us find out this value. How will we find it? We will use Pythagoras Theorem. The square of AA is 6 plus the square of 8, how much will it be? The square of 6 is 36 and 60 is 64, which adds up to 100 and the square of LA is equal to 100. The square of 10 will be subtracted from the square. So what is the value of L, AA here, 10. So what have we found out for this? 10. Okay brother, all the values have been found out. Now, let's solve the question, the actual length of AA and LA in kilometer. What do we have to find out? We have to find out the actual length of LA and AA. So, first of all, see what formula do we have here? We have a formula that is the length of 6, that means the ratio

14:54 into the actual length. Let me convert it into the actual length. I will write it in short form, A actual length, okay, A means actual, L means length. Now, what is the length of the image, brother? That is given to us. Here, we have to find out the length of the image. How much is the length of the image? So, you will write here, what is the ratio of 8 equal to 1 by 25000. One two, okay, brother, we have to find out the actual length in into, write A here. Now, divide 25000 by sed and multiply 8 into 25000 equal to actual length. Okay, after that, what did you say in the last, brother, do you have to do it in kilometers? So, to convert it into kilometers, what will you have to do? You will have to convert it, brother. All the values are given in centimeters. To go from centimeters to meters, type 100 and to go from meters to kilometers, type 1000.

15:41 So, there will be five zeros below. Okay, now see, three zeros are cut off. Three zeros are less than 25. 25 25 4 100 cut off by four. 4 times 8 so what is the actual length that you have here 2 kilometers how much brother so your first answer will be 2 km now let's go to its second part what did you say in the second part bha we have the actual length here the actual length sorry actual area of the plot in square kilometer well before that we have to find out a in this I will also have to find out a in this image length of l a y write a on it ok to find out the same actual length in i k into this so what is the image length of a see where is a and 10 how much is 10 in iba

16:27 25000 into whatever amount you have this actual length now you know it will come on this side and multiply 10 into 25000 how many zeros put five zeros below 100 so to come from meter to centimeter to meter and to go to 1000 kilometers three zeros were subtracted from three one zero was subtracted from 10 this will come to 2.5 kilometers how much brother How much is 2.5 kilometers brother 2.5 kilometers so the first question is done now let's move on to the second part now I will do the second part here in the second part it is said actual area of the plot in square kilometers find out the actual area but what do you have to do before the actual area here you have to find out the area of the image so how will you find out the area image area to find out what is half of the base brother eight base into area what is six subtraction brother 2 4 8 6 4 24

17:15 24 square centimeter this is your area brother now what do you have to do brother image area is equal to the square of k we will calculate you inside the area okay brother and the actual area will come here okay brother so what is the image area 24 in us the square of k means the square of 25000 okay into the actual area so let's rotate it on this side so how many times will you have to write 25000 in 24 times 25000 twice write 1 two and one more time write 1 How much in doti divide, brother? Well, how many zeros did you have to put first? Five had to be put. Two and three, there were five zeros, right? To change the total in kilometers, see, it is written that if you want to convert it into square kilometers, then

18:00 here it is square, so twice, that means double 10 of five, so you have to put 10 zeros below. For five one, two two 4 one pa and for the second also 1 doti 4 pa, convert into square kilometers. To find out the actual area, you see, three and three 6 six zeros, so subtract six zeros, five and one 6, okay, now subtract, see, four zeros are left here, 25 4 100 becomes 400, brother, here then subtract again 25 1 25 and 25 1 25, leaving 15 25 ch 16, how much did it leave here, 16 now let us subtract this, let us see at which it will be subtracted, 8 d 16 8 t is 24 3/2, so what is the actual area, bha Your 3/2 here subtract this also 1.5 square kilometer. This will be your final answer

18:45 brother of question number fifth and here your question number fifth gets completed. Okay, you have to do the same thing in this. See what it has been said, the scale of a map is 1 2 lakh, a plot of land of area 10 km. Your area itself is to be represented on the map. Find the length in kilometers on the ground represented by 1 centimeter on the map. Okay, 1 centimeter on the map has been given to you, so what will you do? Look here, it is of the image brother, here this image length equal to into, you have to find out the actual length, what is the length of the image, I am doing the first part, I have given the length of the image, how much have I given you, ah, here the length on the ground in kilometers equal to 1 in you, how much is your 2 lakh, write 2 lakh below, 1 2 3 4 5 into, you have to find out the actual length We have to

19:33 find out the length in kilometers. Okay, the length in kilometer on the ground is represented by 1 centimeter. It is in centimeters, right? If you want to find out in kilometers, then first send it to that side. 1 * in 2 lakh 1 2 3 4 5 l to get the actual length. So, it will have to do the same thing as it was from centimeter to meter. 100 and then 1000. Five zeros are deducted from five zeros, so what is your actual length left? How much is 2 km left here, brother? 2 km is left. Now let's go to the second part. What has been said in second, we have been told the area in kilometers. Area has been given in kilometers that can be represented by 3 centimeters square on the map. It has been shown on the map by 3 centimeters square, so write it here. I will first write the formula, then I will do it later. I will write here image area equal to k s into actual area.

20:19 Okay brother, so how much image area have we been given, 3 centimeters square, so write 3 equal to k, that means one. In me, the square of 2 lakhs, ek doti ch pa, its whole square into the actual area, so the square of 2 lakhs will be multiplied by this, you write 2 lakhs twice, because it is square, right? Up to the power ek doti ch pa ek doti ch pa equal to the actual area, and what will you do in dividing it, you have to convert it, inside which also you have to see the area written in kilometer square, if you want to convert it to kilometer square, then you will have to do the same thing again, it is centimeter, right, centimeter, so to go into meter, you have to put 100 twice, that means total 10 zeros, like you put earlier ek doti ch pa, deduct brother, these five

21:05 zeros got deducted from pa zero, these pa zeros got deducted from these five zeros, dni 6 6 d 12, so the total came out to be 12, so what was your actual area, 12 kilometer square, okay brother, I had written kilometers above, yes I wrote it, okay brother, so this was your second part, now let's go to the last and final, which is your third part. I have to tell how it will be done, so see in the third part brother, I will do this, there is a little battle left, the third part tells you the area on the map represented by the plot of the land, the area of the map is representing the plot and how much area is given on the plot, son, see, here it is 10 km2, how much is given, 10 km2 to be represented on the map, so you have to tell the area of the image, image area = k s *, then what will we write here, actual area, actual area is also with us here, ok now look at us What to

21:51 find out, this time he said the area on the map represented by the plot of land area on the map, finding out the map means that this time you have to find out the imaginary area and you have been given actual 10 km square. So what will you do, write here, imaginary area is equal to 2 lakh, that means how much do you have to write in one upon, brother, how much is it here below, 2 lakh 1 2 3 4 5, what is its square brother, how much is the actual area given to you in square into, brother, 10 km square has been given, 10 has been given brother here, okay now see, let's solve it, how will we solve it, it's simple, what we have right below, we will write it two times here, so I am doing it, where should I do it, I will put it on this side, okay, there is a little junk left here, we will do it here, if it happens then write 2 l two times brother below one twotie cha pa and write one more time

22:40 one twotie cha pa, how much is there in multiply by 10 above one One zero got cut from the zero, how much is left below, brother two and two become four, and how many zeros are there below, total four in this and five in this, nine zeros 3 4 5 6 7 8, what do we have to do with this now, whatever quantity is left below, now we have to divide it exactly into points, sir, okay, we cannot divide it into points, so what do I do, I take it to centimeters, so to go into centimeters, how many times do I have to do this up, brother, I will have to multiply 10 zeros, so ek doti cha pa 6 sa 8 9 10, how many zeros are left below, brother, no zero is left, the zero above the zero has been cut, brother, so how much is left, 10/4, how much is left, brother, this is the remaining, I will write it here, 10/4 is left, I have to

23:26 write 10/4, cut 10/4, brother, 2 * 2 4 2 * 5 10, if you cut it completely, then you get 2.5 km square area here, brother. Not kilometer, sorry centimeter because I have converted it to centimeters, it will go in centimeters, so this was your final answer here, question number six, both the questions were same to same, in a way the quantity was a little bigger, rest everything is same, I hope you are understanding all the questions well, if you are understanding the questions well, then like the video and subscribe to the channel, those who have not done it yet and some children also keep asking me for the links of the previous chapters which we have done because they are not able to get the videos, so let me tell you that whatever video I make, in the description box of every video, you will find the playlist of every chapter, from there, whichever chapter you want to do,

24:12 go there, you will find all those videos, even then if someone does not get it, then ask for the link or it will be provided to you, all the rest of the questions are the same, which I have told, there are some more questions left from the last, let's do those as well brother, see question number seven, let's do it Here in the seventh I am telling you that you have a map on which a drone has a scale, whose scale is how much, brother 1 20000 rectangle plot, let's make a rectangle, now to explain it better, suppose you have a rectangle, inside which you have also been given the diagonal, look at the values in this, let's name it, here we have been given A B A and B C, so let me name it AB CD, how much is A 32, how much is B C, brother it is 24, so you have to find this diagonal, find out the value of A A, first I am

24:57 applying the Pythagoras theorem of the diagonal, how much is the square of 32 plus, brother, the square of 24 base, the square of perpendicular 32, whose square is 1024 plus 24, 576, if we add both, how much will it be, brother 1600, how much will it be, 1600, what will be the square of 1600, square of 40, right, square If the square is cut from this then what is the value of A? Here your 40 is how much is 40? So this is your diagonal which is 40 cm. Okay brother, now let's start its question. Firstly the diagonal distance of the plot in kilometer. You have to find the diagonal distance or the length of the diagonal. Okay, so what would you write? The diagonal in the model, the diagonal length in the map. Here, we will write P, not image model, sorry image, we will write D, it is

25:43 shape, so inside the D shape, we have to write image diagonal length. Okay, image diagonal length E equal to K, that means scale into the original diagonal D means P here, original diagonal. Okay, however much image diagonal you have, you can see here, 40 is given, how much is given, 40 is what is the value of k. 1 in our 20000 into the original diagonal, we have given here also 20000. It will get multiplied further, so 40 in 2000000 equal to original diagonal now what will we do here brother to divide this, first of all what will we do here, we have to convert it into kilometers, so you know, then how many zeros have to be put because ours was in centimeters, two centimeters to meters

26:29 and then to go to third kilometer, so two and two fours and one five this is completely cut, so 4 times 8, so how much is the original diagonal, brother, 8 kilometers, how much is 8 kilometers, your first question was, that part is complete, let's move on to the second part now what will we say in the second one, that the area of the plot in square kilometers, you have to find the area of the plot within square kilometers, so first of all you know the area of it, to find the original area, you know what will have to be written, write the original or the actual area in the image area into it, or leave it, how will the area of the image be found, length into breadth, so 32 into I will take the square of 24 in this, this is a square of 20000 into it,

27:15 so do it brother, here 20000 will be multiplied twice, how much will be there in 32 in 24 into it, brother one twoty ch, then back one twoty ch this area now we have to convert this, what did he say, see how many zeros were there in square kilometer, the same 10 zeros were there again below one twoty chara pa for one, then one twoty chara pa four and four zeros, so this zero got cut, two zeros are left below, now see what will remain below 32 and 24, I am doing it here, so see in 32 in 24 in this, how much do we multiply by 100, if you multiply here, how much will you get, brother ch ch

28:01 16 16 2 32 3072 how many zeros are there below, what was the actual area, multiply it, this is what you will get, see, put a point above 30.7 2 equal to actual area what will be the result brother kilometer square so your final actual area was how much brother 3.72 km s this is over your question here the seventh one was very simple I hope you must have understood it well let's move on to the next one the dimension of the model of the multi storey building are this so we have given it here first but what do we have to find out from this original that is we can say what will be the new dimension we have to find out so how will we find out the new dimension see the new dimension is equal to will come

28:48 what ratio has been given brother 1/60 1/60 into what is your actual dimension 1 meter so how good sorry I did it upside down I should have written the formula first new dimension I found out what was our model of multi storey building new dimension has been given to us that into what have we found out the actual dimension okay so see how much is our new dimension we have given one here This is the value of / 60 into the actual dimension, so if you multiply it by 6 on the side, then how much will the actual dimension be? Here, your 1 in 60 = 60 meters, brother, how much is 60 meters? After that, let's do the next thing, then however much we have 60 centimeters, to convert centimeters into meters, divide by 100, and this was 60, and it will be

29:34 multiplied on this side, it is equal to the actual length, write the actual length or dimension here, dimension, actual dimension, actual dimension, see brother, two zeros are subtracted from two zeros, 6 6 36, so how much will it be, 36 meters. Now, the final last thing left is 1.25, 1.25 in 60 = actual dimension, so do it brother, remove the point 0, one zero is subtracted from two zeros, 2 5 10 2 * 3 6, you will subtract 5 from 10 75, so AD Here it is brother 75 meters, three answers will come, three dimensions are out, one is 60 meters here, one is 36 meters, one is 75 meters, okay, so the first part is completed, now let's go to the next part, see what has been said in the first, the floor

30:20 area of the room of the building, whose area in the model is, this model is 3d, it is a 3d figure, so inside the model, you have been given the area, 2 k, model area equal to how much, write here, the actual area in k, so how much is your model area, 250 and k, that means you will have to square it, is 60, right? The square of 60 into how much is the actual area, multiply 60 by 250, multiply 60 twice, this is the actual area of the model, now you have to convert this, we will convert it into, the floor of the area of the room in the building, model 250, we will convert it into centimeters per kilometer, so to do this, what do you have to solve this first, let's solve this

31:06 Four zeros will be put below, two two f will be done in meters, we are doing it in meters, sorry, we are not doing it in centimeters, we are doing it in kilometers, one two three zeros are subtracted from three zeros 5 25 5 the 10 will be subtracted from two three 5 3 15 15 6 90 So this is your actual area, how much is it? 90 meters square. This is your first part, let's do the second part of this, okay, what will we do in the second part, look carefully what I told you, in the second part, the volume of the room in the model, whose actual volume is 648 cubic, the actual volume has been given to you, so what is the formula, model volume, model volume equal to k cube inu, actual volume, actual volume, so if you want to find the model volume, then I have written AV, how many times do I have to write the cube of the model volume, that is, you

31:54 60, three times because it is the cube of k and what is the actual volume, where is 648, how much brother 648, so let's subtract it from ch 6 6 6 whose bha is ours this is 6 cc cut g will leave three above only how many zeros are there three below so I will do it here the remaining so the volume of the model AV means how much is the model volume brother how many zeros in three below three zeros one doti so what will we do here we will convert it how will we convert see the type given to you where did it go the question here is 648 was given in cubic meters in divide it friend it is 1000 so something will go to zero point so it is better that you convert it into centimeter cube so what will you have to do for that now to go from meter to centimeter so we multiply by 100 but how many cubes are there here so we will have to put six zeros

32:40 doti 4 pa 6 so from six zero brother three zeros are cut off three zeros are left above so this is how much will be left the volume of our model here one two behind three 3 centimeters cube means your answer will come final 3000 cm Since it was a cube meter, I converted it into centimeters, brother. Okay, it was very small, this is very small, brother. I hope you understood the question well. There are two last questions left, let's do that as well, brother. Let's do question number nine. See, what have you been given in nine? A model of a ship in made up of a two scale. This is 1:250. We have to find the length of a ship. If the length of its model is this, then you know brother, what is our formula, the length of the model, m A. I will write it in short. m means model A means length E equal to k ship length in ntoo. Okay

33:29 brother, so what is the length of the model, 1.2 1.2 What is the value of e K? Ship length in 1/250 into Okay brother. Or you can also write the actual length, if you want to write, multiply 250 by a, so 1.2 in 250 e ship length Remove the point, 10 will appear below brother, zero is cut from zero, multiply the zero 12 p 60's zero l 6 12 d 24 and 6 30, so how much will the length of the ship be? 300 ok, look at what is written above, it was written in meters and we have to find the type, find it in meters, a kilometer etc. so you do n't have to say anything, then your answer will be final, how much will 300 meters come, the answer to this will be 300 meters now let's go to the next, the area of the deck of the ship, if the area of the deck of the model, you have been given the area of the model, do the same,

34:14 you have done the second part, this was your first part, now I am doing the second part, area of model, what will you write brother, area of model equal to ke sc into the area of ship, so see how much area of model have you been given, where did it go, this is 1.6 1.6 = 1 in us, the square of 250 into the actual area of ship, okay now see, the square of 250 comes in this way Multiply it, remove the point of 16, add 10 below and how many times do you want to take 250? Two times so area of ship, see brother, one zero is subtracted from two zeros, after that what will be left with you, let's see here if anything is worth subtracting or not, after that let's see if it will not be subtracted, 25 p 65 is 625 in 16 times the actual area behind,

35:02 now let's multiply it, see brother, 16 16 p 80's 0 added 8 16 times 32 and 8 40's zero four carried, 16 ch 64 and ch 16 6 96 and what will it become, here you have 96 and 4 100 meters square equal to actual area of ship, see, the area of the ship will come, how many lakh meters square area will come of the ship, well, the last third point and the remaining that will be done, now see in the third part, what was told to you in the third, the volume of the model has been given to you, if you have to find out the volume of the model of the ship How much is the volume of 1 kilometer? Okay, so what will you write? Write the same as per your formula. So what will you write first? Volume of model il two k cube how much, brother? Volume of ship into cube. Okay, it's the actual

35:50 volume of the ship, so we have to find the volume of the model, so it will be like this: volume of model il two k cube, that is, how many times do I have to write one upon cube? 250 has to be written three times in cube. 250 250 250 into cube. And it is 1 kilometer, brother, first write 1 kilometer as one. And what will you have to do to convert kilometer into meters, because you have to take it in meters, then you will have to put 1000, oh, okay, to convert kilometer into meters, how many times six times, so I will pick it up and convert it directly here, 1 doti cha pa 6 how much will it be, brother, here it has become six and 3 3 6 39 ti 6 39 three three times. I have written three here, why did I write it here son,

36:36 because here I have written 1000 for one, 1000 for the second. For this I converted 1000 three times for the third one. Okay, so cut it also with three zeros. So first three zeros got cut. Okay, after that 25 ch 100 on top. What am I doing? Wait a minute, I will keep it like this. I have not even cut 25. I will just write two two and two ch on top. 100 three times. How many times will I write 100 three times, so that it becomes easy to cut. How much will I write 25 25 25 below. Cut your 25 4 100 25 4 100 25 4 100. You will do four three times. 64 meter cube will come. Your brother, the total volume of its model, which you had to find out, will come. Okay, so your answer is here, one will come here 300 meter, then 100 lakh meter will come and then 64 meter will come. So here your question number

37:22 nine, complete it same to same. You have to do the 10th one, that the volume of the model is Then the volume model has been given to you, it is volume, it is litres, so it is length, it is only length, sorry, so you will write here model length equal to k into the actual length, so what is the length of the model, four, brother, what is your actual length in 200 into 200, you will have to find that here, so what will you do, come on the 200 side and multiply 4 into 200, this actual length will become 800 meters, along with your actual length, okay brother, if the length is this, find out this, if it is okay, then let's go to the second part, this was the first part, it is said in the second part, if the area of the deck of the ship is this, find the area of the

38:08 model, okay, this time you have to find out the area of the model, so what is the model area is equal to k s into k, what will you put along with it, brother, here the area of the ship, area of ship, okay, so what is the value of k brother 1 in you Write 200 twice, one two into how much area of the ship is given, where is 16 and behind that there is a 2 3 4 meter square, so convert and subtract it, by which four zero is being cut, four zero is cut, 2 times 4 is cut from four, so only 4 meter square, how much will be the area of the model, okay, so how much will be the area of the model, the area of the model will be 4 meters square, finished now let's go to the third part, in the third part it is said that if the volume

38:55 of the model is 200 litres, if the volume of the model is 200 litres, then tell me what will be the volume of the ship in cubic metres, so what will you do, write here the volume of the model i.e. the volume of the actual ship in the cube, the actual volume of the ship, okay brother, so how much volume of the model do you have, 200 litres, 200 take i.e. the cube of 200 meters, that is, how many cubes do we have in a cube of 200 and how much will your actual volume be in this, so look 200 and 200 have to be done three times one two three il to get the actual volume divided by litres we will do it in that we will put three zeros how many three zeros will be put okay now let's

39:43 cut it see what will be cut from the three zeros two and one three zeros two times 4 times 8 times 8 16 16 comes and how many zeros will be added after two two four and one five five zeros will be added one two because here one zero is left one so now it is cut two two four and one five and it will be added together brother meter cube was meter only meter cube is equal to actual volume so this was your final answer of this question your question number 10 has been completed I hope you have understood all the questions well it was a very simple chapter this our chapter has been completed there was just one exercise in it in which there were 10 questions which we have solved so similarity As a transformation size transformation and its next question which was our next chapter 16 both were the same chapters brother you should do both properly after that we will start our next chapter till here if anyone faces any

40:29 problem, any query, any doubt in any question then you can ask me by commenting rest subscribe to the channel brother those who have not done it yet, do share the video with your friends and classmates so that it can help them, they can also understand the question properly and can get good marks in the exam also fine see you in the next chapter thank you

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