CUET PG Applied Microbiology (SCQP03) Previous Year Question Paper Analysis | CUET PG 2026 Exam Prep

Brief Summary

Alright, folks, let's break down this CUET PG 2024 Applied Microbiology paper (ACQP03). The speaker goes through all 75 questions, pointing out a few potential errors by NTA that you might wanna challenge. Plus, there's some gyan on expected cutoffs for DU, BHU, and other unis, along with advice on what to do if your score ain't great. They also solve the paper question by question.

  • Expected cutoff for DU/BHU is around 220 for general category.
  • If score is below 100, consider dropping or private university.
  • A few questions might have errors and can be challenged.

Intro and Paper Overview

The speaker starts by saying that they will solve the CUET PG 2024 Applied Microbiology paper, code ACQP03, which has 75 questions. They mention that some students might have marked 25-30% of the answers wrong, but it's likely due to errors on their part, not necessarily NTA's. However, there might be 2-3 questions that can be challenged because the answers aren't properly justified. The speaker urges everyone to share and like the session and fill out the counseling form to get an idea of average scores and cutoffs for microbiology students.

Expected Cutoffs and Options

The speaker discusses the expected cutoff for the microbiology paper, suggesting around 220 for the general category if you're aiming for DU or BHU. They acknowledge that many students are scoring in the 230-235 range. For average universities, a score around 150-160 might be enough for the general category. The speaker emphasizes that the micro paper was relatively easy, so a good score is expected. If your score is below 100, you have the option to either drop and prepare again or pursue a master's from a private university.

Question 1: Lac Operon

The first question is about the lac operon, asking for the true statement. The correct answer is that the lac operon has three structural genes: Z, Y, and A. The speaker explains why the other options are incorrect, emphasizing that the repressor binds to the operator, not the promoter. The speaker also reminds students to carefully read the options and use the elimination method to arrive at the correct answer.

Question 2: Complement System Activation

The next question deals with the complement system activation, asking for the correct order of events. The speaker points out that MAC formation (membrane attacking complex) should be the last step. By eliminating options where MAC formation isn't last, the correct answer is found to be option number 4.

Question 3: Cell Biology and DNA Replication

This question is from cell biology, focusing on DNA replication. The speaker highlights that DNA replication occurs during the S phase of interphase. They clarify that even if you're unfamiliar with transcription or the specifics of each phase, knowing that DNA duplication happens in the S phase is key to answering correctly.

Question 4: Matching Scientists with Discoveries

The question involves matching scientists with their respective discoveries. The speaker goes through each scientist, such as Beadle and Tatum (one gene-one enzyme hypothesis) and Winogradsky (enrichment culture technique), to arrive at the correct matching. The final answer is option 4, with the specific matches being A-4, B-2, C-1, and D-3.

Question 5: Shuttle Vectors

This question asks for the true statement about shuttle vectors. The speaker explains that shuttle vectors can replicate in both prokaryotic and eukaryotic cells. The correct answer is that shuttle vectors have the capability to replicate in two unrelated hosts. The speaker also clarifies that shuttle vectors have different selection markers for prokaryotes and eukaryotes.

Question 6: Antigen Presenting Cells

The question asks which of the listed cells is NOT an antigen-presenting cell. The speaker reminds the audience of the "BMW" mnemonic (B cells, Macrophages, Dendritic cells) to remember the major antigen-presenting cells. The correct answer is option number 2.

Question 7: Recessive X-linked Traits

This genetics question asks about recessive X-linked traits. The speaker recalls common X-linked disorders like color blindness and hemophilia. By remembering that color blindness is an X-linked recessive trait, the correct answer can be identified.

Question 8: Chain Termination in DNA Sequencing

The question is about chain termination methods in DNA sequencing. The speaker explains that Sanger sequencing (dideoxy method) is a chain termination method because the absence of a 3'OH group in dideoxynucleotides prevents further phosphodiester bond formation. Maxam-Gilbert sequencing, on the other hand, uses chemical degradation and doesn't involve chain termination.

Question 9: Petite Mutation in Yeast

This question describes a petite mutation in aerobically cultured yeast. When the mutant is crossed with a wild-type strain, all progeny are wild-type. The speaker explains that suppressive mutations and neutral mutations are possibilities. The fact that all progeny are wild-type suggests a neutral mutation.

Question 10: L-Isoleucine Formation

The question asks how the formation of L-isoleucine from L-threonine is regulated. The speaker explains that the process is regulated by feedback inhibition, where the product (L-isoleucine) inhibits the enzyme (Threonine deaminase) involved in its synthesis.

Question 11: Agglutination Reaction

This question concerns agglutination reactions, particularly in ABO blood grouping. The speaker explains that excess antibody can inhibit agglutination. The correct answer is that excess antibody inhibits the agglutination reaction.

Question 12: Peptide Bond Features

The question asks for a feature that is NOT characteristic of a peptide bond. The speaker explains that peptide bonds have partial double bond character, are planar, and are rigid. However, they are not linear.

Question 13: Amino Acid Properties

This question involves matching amino acids with their properties. The speaker goes through each amino acid, such as cysteine (polar, sulfur-containing) and aspartate (negatively charged), to arrive at the correct matching.

Question 14: Sugar Derivatives in Bacterial Cell Walls

The question asks which sugar derivative is found in bacterial cell walls. The speaker identifies N-acetylmuramic acid (NAM) as a key component of bacterial cell walls.

Question 15: Matching Molecular Biology Enzymes with Functions

This question requires matching molecular biology enzymes with their functions. The speaker explains the functions of helicase (unwinding DNA), DNA polymerase (filling gaps), topoisomerase (relieving supercoiling), and ligase (sealing nicks).

Question 16: Mycorrhizae Association

The question asks about the association in mycorrhizae. The speaker explains that mycorrhizae is a mutualistic relationship between fungi and plant roots, where both benefit.

Question 17: Denitrification Statements

This question asks which statements about denitrification are true. The speaker explains that denitrification converts nitrate to atmospheric nitrogen and is detrimental to agriculture but beneficial for wastewater treatment.

Question 18: Bacterial Chemotaxis

This question is about bacterial chemotaxis. The speaker explains the two-component signaling system involved, including CheA and CheW. The correct sequence involves CheA interacting with CheW, followed by adaptation and adjustment of the flagellar motor.

Question 19: Antimicrobial Resistance Mechanisms

The question asks which of the listed mechanisms is NOT a mechanism of antimicrobial resistance. The speaker explains that bacteria can alter their target, inactivate the antibiotic, or remove it, but they cannot create a new pathway to bypass the antibiotic's action.

Question 20: Affinity Chromatography for MRNA Purification

The question involves affinity chromatography for mRNA purification. The speaker explains that oligo dT sequences bind to the poly-A tail of mRNA, allowing for its purification.

Question 21: Mobile Phase in Gas Chromatography

The question asks which gas cannot be used as a mobile phase in gas chromatography. The speaker explains that oxygen cannot be used because it can cause oxidation of the sample.

Question 22: Fermented Food Product

The question asks which of the listed options is NOT a fermented food product. The speaker identifies ragi as a crop that doesn't involve fermentation.

Question 23: Viral Genomes

The question asks which virus has a DNA genome. The speaker identifies smallpox as having a DNA genome, while polio, rabies, and HIV have RNA genomes.

Question 24: Alcohol as a Disinfectant

The question asks about the mechanism of action of alcohol as a disinfectant. The speaker explains that alcohol denatures proteins, disrupting their structure and function.

Question 25: International Recognition for Patents

The question asks which treaty or convention provides international recognition for patents, particularly for microorganisms. The speaker identifies the Budapest Treaty as providing this recognition.

Question 26: Gram Staining Steps

The question asks for the correct order of steps in Gram staining. The speaker outlines the steps: spreading a thin film, applying crystal violet, adding iodine, decolorizing, and applying a counterstain.

Question 27: Chlorosomes

The question asks which features are related to chlorosomes. The speaker explains that chlorosomes are found in green bacteria, contain bacteriochlorophylls, and are involved in light harvesting.

Question 28: Primary Metabolites

The question asks which of the listed options is NOT a primary metabolite. The speaker explains that antibiotics are secondary metabolites, while amino acids, ethanol, and enzymes are primary metabolites.

Question 29: Binary Fission Steps

The question asks to arrange the steps of binary fission in the correct order. The speaker outlines the steps: DNA replication, cell elongation, septum formation, and cell separation.

Question 30: Selective Media for Staphylococcus

The question asks which media is used to select for Staphylococcus. The speaker identifies mannitol salt agar as a selective media for Staphylococcus.

Question 31: Germinal Centers

The question asks about the role of germinal centers. The speaker explains that germinal centers are involved in antigen trapping, somatic hypermutation, and antibody production.

Question 32: DNA Forms with Alternating Purines and Pyrimidines

The question asks which form of DNA is produced with alternating purine and pyrimidine nucleotides. The speaker identifies Z-DNA as the form found in this condition.

Question 33: Peroxisome Functions

The question asks about the functions of peroxisomes. The speaker explains that peroxisomes oxidize substrates, break down hydrogen peroxide using catalase, and are involved in fatty acid oxidation in plants and fungi.

Question 34: Density Gradient Centrifugation

The question asks about density gradient centrifugation. The speaker explains that bands of separated particles appear when the rotor is at rest, the centrifuge tube is filled with a gradient, and sedimentation and separation occur during centrifugation.

Question 35: Recombination Frequency and Map Units

The question involves calculating the distance between genes based on recombination frequency. The speaker explains that 1% recombination frequency is equal to 1 centimorgan (cM) or 1 map unit. Therefore, 20% recombination frequency is equal to 20 cM or 20 map units.

Question 36: Asexual Reproduction in Fungi

The question asks which of the listed options is NOT an asexual method of reproduction in fungi. The speaker identifies gametangial conjugation as a sexual method of reproduction.

Question 37: Group Translocation

The question asks about group translocation. The speaker explains that group translocation involves chemically modifying the molecule during transport and is an example of primary active transport.

Question 38: ATP Production from Glucose Oxidation

The question asks about the number of ATP molecules produced from glucose oxidation via substrate-level phosphorylation. The speaker explains the steps of glycolysis, the link reaction, and the Krebs cycle, calculating the ATP production from substrate-level phosphorylation.

Question 39: Coenzymes and Prosthetic Groups

The question asks about the difference between coenzymes and prosthetic groups. The speaker explains that coenzymes bind loosely to enzymes, while prosthetic groups bind tightly.

Question 40: Vector Selection Markers

The question asks about the function of antibiotic resistance genes in vectors. The speaker explains that these genes serve as selection markers, helping to identify cells that have taken up the vector.

Question 41: First Cells at Inflammation Site

The question asks which cells are the first to arrive at an inflammation site.

Question 42: Organisms in Dry Environments

The question asks which organisms can grow in very dry environments. The speaker identifies xerophytes as organisms adapted to dry conditions.

Question 43: T Cell Receptor Interaction

The question asks about the interaction of a T cell receptor with a cytotoxic T lymphocyte.

Question 44: Bacterial Growth Curve

The question asks about the phase in the bacterial growth curve where there is no net increase or decrease in cell number. The speaker identifies the stationary phase as the phase where birth and death rates are equal.

Question 45: Genome GC Content

The question asks about the inference from organisms with different GC content. The speaker explains that organisms with significantly different GC content are likely unrelated and belong to different taxa.

Question 46: PCR Steps

The question asks for the correct order of steps in PCR.

Question 47: MRNA Synthesis in Prokaryotes

The question asks who is responsible for doing mRNA in prokaryotes. The speaker explains that in prokaryotes, there is a normal RNA, polymase A, which is used to do.

Question 48: Melting Temperature Calculation

The question involves calculating the melting temperature of a primer sequence using the Wallace rule. The speaker explains the formula: 4 x (G + C) + 2 x (A + T).

Question 49: RNA Synthesis Steps

The question asks to arrange the steps in RNA synthesis in the correct order.

Question 50: Cloning Vectors

The question asks to arrange the cloning vectors.

Question 51: Most Abundant Protein

The question asks which is the most abundant protein on earth. The speaker identifies rubisco as the most abundant protein.

Question 52: Ecological Interactions

The question asks to match the ecological interactions.

Question 53: Impellers in Fermenter

The question asks about the function of impellers in a fermenter. The speaker explains that impellers mix nutrients, mix oxygen, and stir the medium.

Question 54: Catabolism

The question asks about catabolism.

Question 55: Citric Acid Cycle

The question asks to arrange the following intermediate on the basis of their synthesis in citric acid cycle.

Question 56: Ozone Depletion

The question asks which deplete the ozone.

Question 57: Human ABO Blood Group

The question asks about human ABO blood group.

Question 58: Google and Research Paper

The question asks about Google and Research Paper.

Question 59: Water Activity

The question asks about water activity.

Question 60: Electrophoresis

The question asks about Electrophoresis.

Question 61: Exotoxin

The question asks about Exotoxin.

Question 62: B-cell Maturation

The question asks about B-cell Maturation.

Question 63: Actinomycities

The question asks about Actinomycities.

Question 64: Vertical Gel

The question asks about Vertical Gel.

Question 65: Stop Codons

The question asks about Stop Codons.

Question 66: Rhizobium

The question asks about Rhizobium.

Question 67: Oligo Nucleotide Probe

The question asks about Oligo Nucleotide Probe.

Question 68: Flow of Genetic Information

The question asks about Flow of Genetic Information.

Question 69: Coding Mode

The question asks about Coding Mode.

Question 70: Batch Culture

The question asks about Batch Culture.

Question 71: Replication Cycle

The question asks about Replication Cycle.

Question 72: Cyanobacterial Biofertilizer

The question asks about Cyanobacterial Biofertilizer.

Question 73: Waste Water Treatment

The question asks about Waste Water Treatment.

Question 74: Proteomics

The question asks about Proteomics.

Closing Remarks

The speaker concludes the session, encouraging students to re-check their answers and prepare for future exams.

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0:06 Good afternoon, good afternoon, good afternoon. Come on, come on. As I said, you will solve the paper in 24 hours. As you can see, the paper will be found in 24 hours. This is the case we talked earlier. So here is the CUE-T PG-2000 Purchase Applied Microbiological code ACQP03. All 75 questions. If we talk about it here, all 75 questions. All 75 questions. Now we are going to discuss this here. And we should challenge you here, we will tell you that. So first, you have been killed on telegrams on the

0:56 phone. What happened? 25 or 30% wrong. You have done it wrong, NTA has not done it wrong. 2-3 questions you can challenge that you have answered in the question that the answer is not justified. That answer is not right. On that basis, you can challenge 2-3 questions here. First, share the session, like the session and fill the form of the counseling form. We share the form of the counseling form so that we can tell that in microbiology students how many children are on average and how many scores are on average, so you can cut off you can go there because there are a lot of limited number of seats. So we will check here how many children have come here with the number of friends.

1:43 You need to fill your name, number, subject and how many scores are. Look at the counseling form. Fill this counseling form without wasting time. Now we start our session. I will tell you that the paper of the micro paper is so good. We will tell you about the expected cutoff experience. If you are talking about DU or BHU, you have to take it up to 220. You have to take it up to 220 if you talk about general category. Because how many children are coming to 231, 235, they are coming to a lot of children.

2:30 You also tell your score. How many scores are coming to this general category? In the U-Hiding, you have 10 or 15 seats, but in microbiology, you will get the score from the U-BHU. So, this is the expected expected cutoff for the ESP225. This is your cutoff for the SQP03. This is the first round, I think it is your first round. Besides, if the chance of the second round is very low, the second round will also be the 210. And if you have any If you have to talk about the average university, that our average university will be able to

3:16 get to the average university. You need to get to the average university. You will get to the general category. Then go to the micro admission. Because the paper is easy for micro. So, it is more than 65. If the child is ready, he can give the answer in a hurry. Now, you will be able to get the answer in a month. and you will think that we are ranked, so that is not possible. I am talking to you every day, the child is working with the whole year, the child is working with consistency, the regular class, questions, doubts, so many of them are coming from the race. Yes, we will do everything. We will do everything, the next is the Zoology. First of all, the Micro, then the Zoology, then the Life Sciences, then the Botany. Okay, experience, go. Share and like the session. And if you will see one more,

4:06 if you will see here, लग रहा है कि मेरा स्कोर अच्छा नहीं आ रहा है तो तुम 2026 के लिए अपना प्रिप्रेशन कर सकते हो बई ठीक है I will give you a number here, 913659724. This is your number. If you are below 100 score, either you drop it or you have another option that you have to do from a private university. You can do your master's in a good way. Now you drop it, so you have to study it. And you can join here for 2026, CVT, PG. If you think that I have to do it, you can drop. And those who are in this category, don't need to delay here.

4:53 Let's start preparing for net December 2000 for the purchase. And with that, we have to discuss questions here. You also know your answers and doubts. Okay. There will be both answers. Ruhi, there will be both answers. There are a few mistakes in Zoology. We will do all the time now because we have to solve the charger paper. Okay, let's start our race. First question, true statement about the lehkoperon, molbayo question. और पहला अगर आप देखो तो correct answer statement पे question पूछा गया है लेकोपरॉन इस अंडर positive regulation through CRP इसके पास तीन structure gene होते हैं कौन-कौन से

5:43 होते हैं Z,Y,A तो B तो statement true गई अब B statement इसमें नहीं है और ये बच्चे न वाँ पर गडवड यही करके आते हैं, option clear out नहीं करते हैं, कोई repressor promotor से bind कैसे कर सकता है, repressor bind करता है operator से, जब भी पढ़ा है हर बार यही बोला, यह याद रखो, रटा बान के रखो, repressor operator के लिए हो तब promotor से जाके कौन bind करता है, या तो activator और उसके साथ दोनों के अंदर दिया है मैं लगा 4 option और A option का B हमारा 100% करेक्टा जो हम कर भी चुके लैकोपरोन का expression होता है इन presence of both glucose and lactose नहीं glucose की presence में क्यों करेगा? lactose की presence में

6:33 होगा इसकी presence में होगा लेकिन glucose के लिए तो चाहिए ही नहीं वो तो D option गलार and option number one. If you just look D, that will be removed. The simple elimination method is to eliminate things and solve it. Time is still a good time. You can see that the option is like D, it will be like this. Very good. One answer is. Larkopron, the name of the child is Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of Larkopron. Larkopron is in the name of L The paper response record is different and the answer is different. Don't do that for any child. We have matched the answer with the first question ID. This

7:19 is your question ID. The answer will be A. What will be A? That will be A. It will be 4797. Okay, let's go. You also tell your answer. You also tell your answers about what you did and share the session. The next one is Compliment System Activation. It means that it is an immune question. You ask the correct order to ask you. What will happen first, what will happen after that and what will happen after that. If you look at the order, you say C1. We have learned one thing. Compliment System is the main part that it is called MAC formation. It means that it is called membrane attacking complex.

8:05 तो यह तो last है ठीक है यह तो last यह हो गई अगर यह last है तो यह D जो C option है यह last में होना चाहिए यह शुरुआत में तो होना ही नहीं चाहिए तो that means elimination हो गया भई इसमें तो directly हमारा answer number 4 आ गया तो Mac formation शुट भी the last one और C से पहले यह इसलिए क्योंकि Mac formation में C5 involved होता है So if it will become C5, then go to the MAC, then D and C will be. Then C1, C3 Convertase or Binding of C1 to this. This is the first thing. If it will bind C1, it will be classified in classical path. This will be a process, then go to C3 Convertase. Then this will be and this will be the last one. So what is your answer? Option number 4. Very

8:53 good. Next question. Yes, there is a question of cell biology. Who was the CPL of cell biology? I told them clearly that this is the most repeated question. It is the most repeated question that you should ask. You should ask that DNA replication is on the same way and that you have sentryol duplication. This question is asked for so many times and here is the word here. Let's see, you don't know what the transcription means. You don't know what the face is on the same way. So when you have a messenger RNA and a transcription, you don't know the phase. This is why you believe that it can be new. This is also been told. In this phase, we make RNA, we make proteins, but it was not. But it knows the duplication of

9:42 DNA in which phase is in this phase. In this phase, which is in which one is in the inter-phase. So a child has a message here, that I have checked the first answer. Then you have the answer wrong with your own. Check the question ID. I don't see the video, I'll tell you later. The answer is 1160 question id here is third. Third is 4599. What is the correct answer? You have to check it here. We will do everything first. You have to learn the knowledge of zoology in micro. learn more about your attitude that I will not see the microphone or not do this. This is also a good knowledge.

10:29 Next question directly match question. What did Benjarnik, Sergey Vinos, Gredisky, Biddle and Tentum, Smith, Nathans and Warner Arbor? What did we do? What did we do? Simple matching. What did you ask? Correct answer. If we look at here, Benjarnik वन जीन वन एंजाइन हाइपोथीस दीती फर्स टाइम आइसोलेशन होगे रहा था रिस्रिक्शन एंजाइन या फिर इन्होंने एंडिच्मेंट कल्चर टेखनीक दीती वैसे ही विनो ग्रेडिस की जो यहां पर यह है यहां पर सबसे इंपोर्टेंट देख लेते हैं जो बी

11:21 I have done the matching question of the question. You check the same thing and check the same thing. So, when we have done this, we have done the same thing. So, your answer is C and 1. The answer is 2. What will 1 come? 4. What will B come? 2. What will C come? 1. We have done D and 3. तो answer number 4 का answer है B, next question आ रहा है, देखो, कौन सा is or are, मतलब more than 1 B correct हो सकता है, एक भी correct हो सकता है, true पूचा है, shuttle vector, shuttle vector कौन सी vector, जैसे हम badminton खेलते है, shuttle होती है, कभी इधर, कभी उधर, मतलब ये वो vectors है, जो pro carry-outs में भी use हो सकते हैं,

12:09 और u carry-outs में भी use हो सकते हैं, इधर से भी इध So, the vector which has the capability to replicate only in related organisms can be used in the same way. Now, this is wrong because we have said that it can be used in pro-creots or u-creots, so this can be used only for fake-y. यह दोनों में कर सकता है, Vectors जिसके पास Capability है, दो Unrelated Host में जाने की, Yes, यह बिलकुल सही बात है, तो जहां पर A है, वो Option तो पहली हट गए, B वाले रखेंगे, और अगर देखो तो इन दोनों में ही CVR है, तो यह भी होगा, कि इसके पास दो Origin of Replication होगे, 1 for Pro Carriors and 1 for U Carriors. No selection marker has no one with the shuttle vector. No one with the same selection

12:58 markers. It is different for u-creots and here it is different for pro-creots. So if it happens, it is not a wrong statement. So here the option is removed from d and the answer will be option number c. Clear? Next question. See how many questions have come in this question? This is so easy question, I gave it again and asked them, which antigen presenting is not? Otherwise, what is the question? Which antigen presenting is? No, I had taught you to remember BMW. B-cell present as an antigen presenting cell, macrophages, dendritic cell. So this is, this is, this is, this is. What will be the answer? Option number 2. Yes, very easy question. चलो बैइ अगला question

13:43 genetics से आया हुआ है question ID 1199 और यह question तुम्हें CPL में करवाया था तुमसे आया था genetics में disorders आते हैं CPL में तुम्हें सारी बाते करवाई थी ठीक है 157 में tier 2 मिल जायेगा चलो बताओ recessive x-link trait पूछा हुआ है बैइ एक्स-link में हमने कौन-कौन से disease याद करी है देख disorder होता है ऐसे अगर तुम अल्बिनीजम की बात करो तो अल्बिनीजम जो होता है यह भी तुम्हारा कैसा disorder होता है यह भी तुम्हारा ओटोजोमल डिसॉडर होता है यह भी तुम्हारा ओटोजोमल

14:29 डिसॉडर होता है लेकिन इसकी स्पेश्यालिटी क्या है यह डॉमिनेंट होत से भी स्को सॉल्फ कर सकते थे कि अधिक लाइंड नेस हमें चिला चिला के पढ़ाएं कि कलर ब्लाइंड नेस हमारा कैसा डिसोडर होता है एकस लिंक ट्रेट होता है कैसा होता है एकस लिंक और एकस लिंक में भी कैसा होता है रिससे जनरली यहां पर रेड और ग्रीन कलर के बी If you have written the provisional answer and you have matched

15:18 the response record, then you will not have to check the answer from the question ID. Or you will have to do it. Share the session and share it. Let's go ahead and read it, because we have to use 4 papers. Which technique? Chain termination and DNA sequencing. Termination is when it becomes a structure, which can't be done. Maxim Gilbert is a sequencing method, of course it is the old time, but we use chemical degradation method as it is in the compound, the chain breaks. So here there is degradation, there is no stopping. आगला है Sanger Dideoxy, yes, Dideoxy आगे न, हमाई पास DNTP होते हैं, तो process चलता रहता है, Dideoxy, DDNTP,

16:08 मतलब यहाँ पर कोई 3'OH नहीं है, तो phosphor diastro bond ही कैसे बनेगा, कोई नया structure आखी कैसे लगेगा, तो that means Sanger's method जो होता है, वो chain termination method है, next generation sequencing या shotgun, यह दोनों ही आपका third generation sequencing में आते हैं, और When a petite mutation is isolated from aerobically cultured east, you have a season presence here and you have a mutant phone present. What have you done? You crossed with wild type strain. You have seen that the mutant variety is isolated and you crossed with wild variety.

16:57 The progeny obtained is all wild type. बच्चे बने यहां पर जितने भी सारे के सारे बच्चे बने हैं इक में एक भी मुटेंट नहीं है सब वाइल का इपके है तो बता हुई कैसी मुटेशन होगी देखो सप्रेसिव मुटेशन जन्रली एक सेकिंड मुटेशन होती है कैसी मुटेशन होती है सपोस्पोस पहली ब effect को suppress कर दिया, यानि कि आपको normal कर दिया, neutralize एक mutation थी जिसकी वज़े से पहली बार आपको दिक्कत हुई, अगली बार एक a.c. mutation हुई जिसने पहले वाले जो आपका क्या था effect था, इसको suppress कर दिया, वो यहाँ पर

17:46 suppressive mutation कहलाती है, तो यह तो answer नहीं होगा, neutral mutation का मतलब क्या होता है तो यहां पर हमें यही लग रहा है कि सारे के सारे वाइल टाइप बने हैं यानि कि यहां पर कैसी मुटेशन होगी मुट्रल साइलेंट मत समझना साइलेंट का मतलब क्या होता है कि यहां पर इस तरीके से मेरे पास जी एनने की जो सिक्वेंस प्रेजेंट थी यह आपकी यहां

18:32 If you think that the paper is not good, then you need guidance on this number. You can fill the counseling form in this number. If you want to go to December 2025, for the net, or you want to give you a CUE paper in 2026, तो तुम्हारे लिए यहाँ पर एकडम बढ़िया पैच है डाटिस जिनों 2.2 चीक है अगला कोश्चन कौश्चन है बाई अगला कोश्चन अच्छा यह भी मेरा ही कोश्चन है क्या के रहें एंजाइम सीक्वेंस इंवाल्ड इंफोर्मेशन अफ एल आईसोलूसीन देखो य

19:22 These are the questions that students can't remember in detail on the CUT level because it is not a process to ask very frequently. We give them the time to study that you have to study, that it is very important or not. This is not the way. I told you that if you go up 220, then you will get DU, BHU and you will get a average university on the 1.500 to 160. तो यहां पर तुम्हें बोला है कि तुमने यहां पर L-threonine से क्या बनाया है L-isoleucine बनाया है और तुम बताओ कि यह process किस तरीके से regulate होता है पहला है feedback inhibition feedback inhibition मतलब क्या होता है यह substrate है यह product

20:09 है यह enzyme है अगर product अपने ही बनाने वाले enzyme को block करते इसका मतलब feedback अच्छा नहीं दिया ह If you inhibit your enzyme, it is feedback inhibition and we have all of them studied glycolysis. What is competitive inhibition? When you have a substrate binding site here, who binds to this inhibitor? It is competitive inhibition. In non-competitive inhibition, we don't bind to substrate. We bind to another side and we do competition. So let's understand this process here. यहां इस तरीके से हमारे पास L-threonine present है तो यहां

20:57 पर सबसे पहला जो step होता है उसको कौन conduct करता है? Threonine DM-A-S Threonine DM-A-S जो होता है वो क्या करता है? L-threonine को 2-ketobudyrate में जो है convert करता है यहां पर 4 अलग-अलग steps होते हैं और आपका ultimately isoleucine बनता है और यह reaction आपकी chloroplast में चल रही चल रहा है यहाँ पर आपके हिसाब से चल रहा है feedback innovation हमारा जो product था इसने अपने ही बनाने वाले enzyme को क्या कर दिया block कर दिया तो यह आपका किसका example है experience यह आपका feedback innovation का example है generally students के point of view से यहाँ पर एक student इतना नहीं पढ़ पाता है

21:49 वो इसको skip कर सकता है क्योंकि तुम 300 में से 300 तो व चलिए बाई अकले question की तरफ आगे भड़ते होएं नेक्स के रहा है कौन सी statement is or are true है about aglutination reaction aglutination reaction ABO blood grouping में पढ़ते हैं ABO blood grouping जिसके अंदर जब hypersensitivity है कौन सी hypersensitivity type 2 और मैंनो उसमें बताया था अगर कोई भी person है 2 person हम यहाँ पे देख रहे हैं जिसमें एक का जो blood group है वो A है और दूसरे का blood group भी है लेगे हमने हाँ पर क्या कहाता है थोड़ा सा हमने हाँ पर इसका जो blood है वो इसके अंदर transfuse किया है लेकिन थोड़ा सा यह जो reaction होती

22:36 है यह थोड़े में होती है यह जादा में होनी चाहिए तो हम क्या बोलने है थोड़े म चीज़े कम होनी चाहिए तब आपको बंती होई दिखाई देते हैं जैसे आप बलड गुरूपिंग करते हो आप अपने खुद भी लैप्स में हम यह सब परफॉर्म कर रहे होते है तो एक्सेस एंटी बोडी इनिबिट कर रही है एगलोटीडेशन रियक्शन को सही बात है ए Antibody titer is the lowest dilution of the serum in which agglutination reaction

23:24 is observed. Yes, as I said, the less it will be the better agglutination reaction. Okay, so here it is the titer in the lowest dilution of the serum in which agglutination reaction is observed. Lowest dilution is not the lowest dilution. This dilution has been added here. So this answer will not be B. So what is the answer sitting here? Option number B. So that means if this is the idea, then you have to see B answer. Many students are watching B. They have seen 1, 2, 3, 4, and I have written this answer. And in the answer key, B is wrong. You see their question id's then match your answers with the question id's. Next question.

24:15 Not a feature of peptide bond. Not a question. Not a question. The first thing is that peptide bond is not a feature. You have also done with the question PQRS and multiple options. Yes. You should get HCU 188. Is there a partial double bond character? There is a big bull. Is it planar or peptide bond? Yes, you can see it is made of peptide bond. How is peptide bond? Is it linear structure? Yes, it is rigid structure. So if we ask not, we say that it is not linear. It is not linear. So question id will answer 1197. Here is 3. Or 4747. What will be the question id? It will be C. चलो

25:02 अगले कोश्चन की तरफ बाई यह देखो यह भी कोश्चन तुम्हें सीपील में करवाया था कि नेचर ओफ अमीनो एसिट से कोश्चन आता है हां जी सिस्टीन कैसा होता है सिस्टीन पोलर अमीनो एसिट होता है और यह सलफर कंटेइनिंग होता है एसपार्टेड हमारा स because we have positive charge on it. Let's go here. Let's see. We have to match side chain. What will we do with Sulfur containing? A answer will be 4. What will you do here?

25:51 You will be wrong here. Then how will the Aspartate be? B is third. B is third. Then you will be wrong. Then you will be third. We will first click on the question ID 1 1 7. We will match with ID. This answer is 3. That is 4 6 6 3. With the question ID you have to check with the answer. With the question ID. We are thinking that there is no interest in the solution. There is no interest in the solution. There is no interest in the solution. There is no interest in the children. There is no interest in the children. No. We do the work and don't do the paper. No. When the children demand, they will do it. Sugar derivatives is found in bacterial cell wall. Bacterial cell wall is one of which

26:39 sugar derivative is made from sugar. It means modified structures. Lipid is called lipid. Lipid is a lipid structure. A and B is not. A, A, 3 and 4 is C. N is acetyl muramic acid for sure. NAM molecule is a NAG which is not given. फिर दिया है D-galactosamine नहीं जो यहां पर यह structure है यह glucose या फिर किसी भी sugar-dried structure नहीं कहला रहा है क्योंकि अगर आप NAM देखो तो NAM molecule के अंदर हमने modification करी है उसे हमने carboxlic acid जैसी चीजों में convert करके देख रहे हैं, modification करवा रहे हैं लेकिन इसके अंदर ऐसा

27:32 नहीं हो रहा अगर यहा Tiga, option number 3. So, next question. यह तो बड़ा अच्छा कोशिण है, Molecular Biology, Matching, Matching तो बने गई थी, हरेक कोशिण में करनी है, बहुत सिंपली पूछा गया है, हरेक का काम पढ़ा हुआ था, Helicase का काम है, जितने भी Bonds बनते हैं, उनको हटाना, Hydrogen Bonds को Break करना, आपके जो इस तरीके से रहा अप्लिकेशन, फोर प्राइमर को हटा के उस गाप को फील करना ठीक है तो रिलेक्स कोन करा रहा है सूपर को अभी-अभी कहा अन्वाइंड करने का काम किसका है ताकि रैप्लिकेशन फोर्क

28:18 बने हैलिकेस सील कोन कर रहा है निक्स को लाइकेस कर रहा है और हटाना प्राइमर को गाप को फील करने का Next motion. Mycorrhiza is an association of mycorrhizae. So this is your ecology question. Tell mycorrhizae. The first time population interaction is told in that class. Again, I will tell you about CPL. This is your mutualism. Which is your mutualism? In which both species benefit. And in mycorrhizae, who

29:09 have FNGI? Which is your heterotrophic. And here we have higher plants roots are involved in the roots of plants being autotrophic, what will it be? It will be food and it will absorb extra things in the water for the plants. So what is roots and algae or not? What is roots and leaves? We say here is our roots and fungi. Which is roots and fungi? So the third option is the option. option number 3 4607 yes check it next ponzi statement about denitrification are true

29:58 denitrification nitrification not doing correct question atmospheric nitrogen easily used as a source of nitrogen in bacteria use not to do denitrification converts ultra process तो यहां पर A option नहीं अगर A नहीं है वैसे तो elimination करोगे न तो इसी से हमारा answer भी आ रहा है जहां पर होट गए और answer तो B आ ही गया हमारा बाकी देख लेते हैं denitrification में हम opposite लेकर आ रहे हैं yes nitrification से जो आपका यहां nitrate बनेगा उसे ultra ले जाओ फिर से atmospheric nitrogen में convert कर दो तो यह क्या है आपका detrimental process है agriculture वगेरा में यह use हो रहा है और यह beneficial है wastewater

30:45 treatment के अंदर yes तो हमारा answer क्या हो जाएगा इस हिसाब से option number two ठीक है चलो next question चलो पेरा question आगे बई यहां पर chemo-texics यानि कि यह आपका bacterial signaling से question आया है भई यह question आपका experience कहां से आया है bacterial signaling से What happens in the bacteria? You get to see two components signaling. You get to see two components signaling. So, we have a receptor here. Sanjana, A is not correct. You have seen this answer wrong. B is correct. Go check it again. I

31:33 said that you have mistaken it again. यहां पर आपके पास सबसे पहले क्या होता है वह ची ए और यहां पर ची डबलू होता है यह ची ए जो होता है हमारा सेंसर काइनेस क्या होता है सेंसर काइनेस जो हमारे मॉलीक्यूल को सेंस करता है कि यह कीमो ट्रेक्टेंट है कीमो रेपलेंट है उसके बाद ची ए जो है यह � and tell you that it is attractive, so you can add further and if you have chemo or repellent, then you can go back to the back and do a tumbling or stop or do not go back. So this sequence has been done. So you have to

32:22 tell you what you have done in this sequence. This is a simple question that has been asked here. Let's tell you. What do we say? Adaptation. Adaptation means you want to go forward or go back. So this is the most important response that I have to go forward or go back. So here will be the end of B. This is the right answer. This is the right answer. Who will attract from the flagellar motor switch? This flagellar motor switch is the flick protein. What we find for the interaction here is to find response. Response means that we adapt to the flow of the motor. So here is the adjustment of the motor. यानि कि B से जस्ट पहले यहाँ

33:11 पर A होगा चलो भाई उसके बाद कहा रहा है कि यहाँ पर आप interact करते हैं चीप रोटीन से तो सबसे पहला काम हमारा यह होता है कि हमें चीप रोटीन से interact करना है चीप रोटीन से interact करने के बाद हम अपने response regulator को क्या करते हैं activate करते हैं यानि सबस and what will you show us in option number 3? Check with ID. You should answer 1158 here. 4591. Check with ID. Many children have been getting worse here. Let's go ahead and add another question. Which of the following

33:59 is Notam Mechanism of Antimicrobial Residence. Antimicrobial is one way. Antibiotics. एंटिबायोटिक्स तो ठीक है लेकिन अब और्गानिजम भी तो खुद को मोडिफाई करता है कि अच्छा आख हमारे उपर एंटिबायोटिक्स पैनिसलीन को लाते जा रहे हो तो क्या हम पैनिसलीन से मरते ही जाए तो यह थोड़ी चलता रहे गा यहां पर नहीं हमें उनसे � में उपर इसका कुछ असन ही होगा, निट्रलाइज कर दूगा, मलब एक्षिन आया और मैं उसको निट्रलाइज कर रहा हूँ, निट्रलाइज कर दूगा, जैसे हम बोलते हैं, बफर निट्रलाइज करना, निट्रलाइज कर दूगा, या फिर मैं उस, जो भी चीज आएगी,

34:48 But he never thought that this antibiotic works with this pathway so I will change it. I mean, penicillin is getting cell wool so I will change it. You go and stop DNA replication or go and do something else. No, he will do this. He can alter the target of his target. Yes, penicillin can be a little different. You go and the target is a little different. Because we have learned that penicillin has a beta-lectam ring. बीटा लेक्टम रिंग होने की वजए से अब खुद को रेजिस्टेंस बनाने के लिए उन्होंने बीटा लेक्टमेस दे दिया कि अब मैं बीटा लेक्टमेस बनाऊगा इसकी लेक्टम रिंग को तोड़ दूगा अब पैनिसलीन वहाँ

35:34 पर है तो बट काम नहीं कर पा रहा है उदको निटिलाइस करवा रहा है इन एक्टिवेशन करवा सकता है जैसे अभी एक्जाम्पल दिया बीटा लेक्तम लेकिन एक नया पाथवे वो नहीं बनाएगा कि मैं एक नय पाथवे से जिन्दा रहने की कोशिश करता हूं नहीं ये उसकी कैपडिलिटी नहीं होती क्यूं Do it too, but it has asked you to resist yourself. How do you resist yourself so that you don't have any action? So this path way cannot come in resistance. We can change the target, remove and neutralize. But this will not be done. Next question, it's a very easy question. I have made a column like this.

36:20 आई हैव एम रन ने आप भी बता दें आप देखो खुली बता दोगे आर आर ने और देखो टी आर ने अगे आर ने मेरेको इस मिक्ष्टर आप आर ने में से सिर्फ वह वाले स्टक्चर चाहिए जो इस ओलीगो डीटी वाले स्टक्चर पर जाके पाइंड कर जाए ठीक है इ MRN में कोई structure जो आयन वाला नहीं हम मतलब आयन exchange से क्यों करेंगे क्योंकि उसके अंदर ये बात भी कही गई है Oligo DT आयो वर्ड का मतलब होते हैं कि लगबग 10 से 15 T structures present है T bind करता है A से बहुत सारे A से ही bind करेंगा तो यहां पर इनकी binding affinity की बात हो रही है कि कौन इनसे जाके bind करे

37:08 It is not on CRNA but on MRNA. This MRNA is especially special for purification. Sometimes it comes by chance because such a technique has asked by the way to swim. It has to be a little bit of a question. This is a net level question. It becomes a statement and you are asking about reverse phases. Tell me, when Oligo T is talking about phases, we didn't have to find affinity to bind to this T. Affinity is like an antigen, antibody, enzyme, substrate, which binds to you. The answer is 2. Clear? Next. Peroxism, Shelly Mambul, Dil. Note. Who will you not use as mobile phase? In gas chromatography.

37:59 अब ए मेरे को निया पता, गैस क्रोमेटोग्राफिक है, लेकिन मैं यह सोचूंगा कि मैं किसको यूज नहीं करना चाहता हूँ. चार ओप्षन दे दिये, ठीक है. मैं मोबाईल फेज है, वो सब्स्ट्रेट के साथ मूव करके जाएगी. मेरे पास चार ओप्षन है. मैं उस च अब आप option देखो nitrogen, helium, hydrogen ये कुछ ऐसी gases है, they are not that much reactive, जो हमाई sample के साथ mix होके उसका oxidation अगर करा दे ये उसमें कुछ chemical modification कर दे नहीं कर सकता, लेकिन oxygen modify कर सकता है क्योंकि वो oxidation कर देगा, अगर oxidation हो गया तो मेरा तो substrate खराब हो रहा है, मैं sample

38:46 को तो purify कर रहा था using chromatography, वे उसमें तो हम ऐसे चीजों को नहीं चाते हैं इसलिए आपसे नोट पूछा था और आंसर होना था option number C. Clear? Next. देखो ये थोड़ा सा direct वाला question है जिसको पता हो क्योंकि यहाँ पर पता होने की बात है कि कौन fermented product है और कौन fermented product नहीं है. कौन सा इसमें से fermented food product नहीं है आपको यहां पर correct answer देना है तो यह आपको इहां पर इन्होंने 4 options दे रखे हैं ठीक है 4 options दे रखे और इसमें उन्होंने answer दिया है option number yes रागी क्योंकि रागी कुद एक फसल है भई इसमें fermentation का कोई

39:32 रोल नहीं आना था लेकिन बागी तीनों के तीन If you have to read the paper, you will learn the same way. If you have to ask the question, you will increase the same way. What mistakes are I? What are my drawbacks? I want to learn it if someone gives it again. Because there are many of us who are giving BSE and who will not drop and they will think that I need DU or BSU so I will drop it again. So now the time of preparation is to have this. If I have a learning question and I don't know it, I will skip it. Because we have not a target of 300 from 300 and 250 from 300 and it should be correct. Okay? Last

40:23 year there was a question in which you asked directly products. Next question. Which one? I have been asked for a lot of CPS and if there is an app-child sitting here, they are telling them every time, which one virus, which one genome has to be found. I have to look at questions. And I will not leave questions. He will ask for questions. He will ask for life sciences. He will not give it to micro because it is subjective. He is asked for DNA. Yes, smallpox. Pox, severity family, gets to see DNA genome. Whether it is polio, rabies, HIV, it is RNA. But smallpox, DNA is also learning. Learning in micro is one genome point and other

41:13 diseases, bacterial disease, viral disease, matching. So, what is the learning? What is the work of the disinfection of alcohol as a sanitizer or disinfectant when you are using alcohol? In labs there are ethanol. If anyone has worked in labs, we have to do it every time. We have to wipe it with ethanol, clean it with ethanol. What is the work of the structure? Does it make a cateinic surfactant in our structure? or it is

41:58 an alkylating agent. What is alcohol? It will be an alkyl group. It will not add the oxygen structure. If there is no structure or bacteria, it helps their protein or structures to degrade or denature. And this is what we have not learned. But if you have studied biochemistry, it comes to it. Protein denaturation. We have learned from which way you can denature proteins, urea, different salt concentration and all of the work is different, it's different to break the bone but denaturation. So I think that we have only sanitizer disinfectant, so this is what we have to do in the micro. If you are

42:44 showing it from the options and alcohol word, this is called smartness. which is a good topper, will be thought about it and next time you have to think about it and practice questions. Once you do it, you have to think about it and yes, something like this will be gone. Add biochemistry, cell bio, and that concept was used to be done and protein denaturant is working. Okay, see again, this question I have said many questions directly ask and they come in extra that if you don't come just skip that you can skip that which treaty or conventions because many are related to you know

43:35 biodiversity You have searched a micro-organism, being a microbiologist. You can see that this new feature shows me. I discovered it and you want to patent it. international level. If you get it out of every place, it is registered that you have discovered that. So that means international recognition that is received is only for 4 of 4 patents but microbiology The three of us have to patent on the international level and I will tell you that I have done it the first one. They are

44:20 also the patent but not for micro organisms. The 4th number was the budapest. Let's see, last time we asked the question, we asked the steps of gram staining and this time it came again. Gram Staining of the Bacteria, correct answer, steps, what is the first step and what is the first step and when I start gram staining, no other person or CPL, I told you that we take bacteria on the slide, we do a little heat kill, we are doing a little smear and then we start our procedure, heat kill is always said, if you have heard, spread thin film, air dry by heat killing

45:07 अफकोर्स, नमबर वन उसके बाद सबसे पहली चीज हम लोग क्या डालते हैं? क्रिस्टल वॉयलेट आई थिंग, तो सैकेंड नमबर पर क्या आना चीए? इस सिमेर के उपर क्रिस्टल वॉयलेट डाल दो, तो मतलब C के बाद B आएगा, तो आपका यहां पर C के बाद B, C के � Who will come here? We will add iodine, why will we add counter strain? It will come in the last one. Decalorizer will come before counter strain? No. So, here we should come before A. What will be the answer? Option number 2. I thought the paper was good. Wow, very easy questions came. I was a teacher, but I have studied that. If you have a focus, you will do it. But if you are a

45:54 CPL student who has a CPL, then there will be many things of course. Because every time the level goes high. You will not give this. I have made this last time. I will give this last time. No. If it was last time, the competition, number of students will be increased. So, it will increase the level of exam. So, it will increase and increase. This paper of course has been a little bit, but in the easy category. Okay, just add some smartness. Let's see next question. Missed sense mutation has come. Okay, ma'am will tell you about this. Let's see. Which feature here is chlorozoom related? Chlorozoom. Chlorofilm is also a chlorozoom. Correct answer has been asked.

46:45 It will be in green bacteria, light harvesting, but I don't know why it has chlorovert. So A, A, I gave 4 options. Now it contains chlorophyll A. It doesn't have A because chlorophyll A is in your green plants, in cyanobacteria, in algae, in which paper is? Microbiology paper. Okay, we are solving the micro paper. So here, your chlorophyll A is not in it. So B has no answer. So B has gone. Let's go, one thing went on. Present in green bacteria, bacteria is present in bacteria. Then there are bacteria chlorophylls present. B is B, D is that chlorophyll is B, so this is bacteria. C option should be. There is no one, there is

47:35 no one, only there is one. If you see this, I know C, so you remove the answer from elimination method. What are galactolipids? Galacto is a sugar with lipids. You can read it in your normal membrane. But the chlorozoom structures, like peroxizome, lizozome, their membrane is made of phospholipid. It means phosphid plus lipid. Here a membrane is made of galactose plus lipid. Here there are phospholipid normal membranes. So, these points are a little important. Next question. Last time question came from these four who are working on secondary metabolites? I asked them about the primary, which means that they are like the body or like the

48:25 body? That is the question. Antibiotics are like the secondary metabolites, which are not primary because they are not so important. But I need amino acids so that I can make proteins, ethanol, enzymes so that I can have any reaction process. But why do I need antibiotics in my body? I am getting it out of the way. I have a secondary need, I have no primary need. It is also about bacteria. Which primary need is not? Option number 2. Next question. Next question is 32. Tell yourself what answer you want. 32.

49:32 because binary fission related to raw shape and proctorioid sequence will be elongated, will be separation, will be septum formation and will be replication. You know that binary fission is division. Divisions will be separated. So that means this option B will be last. That's why C will be removed. Now if you have three, C, D and D. What will happen first of this separation? DNA replication या septum formation. Septum formation मतला बैक्टिरिया के अंदर कुछ इस तरीके से membrane बन गई होगी जिसमें एक तरफ इधर, एक तरफ इधर DNA आ गया होगा. अरे जब DNA replication होगा तभी तो septum formation होगा. तो यहाँ पर आपका जो B हमने कहा है, जो B हाँ पर हम कह

50:21 रहे हैं, इस B के अंदर T आएगा या C � Now, before that, the elongation of the cell or the replication of DNA. So, if you look at this, our answer is gone. Answer number 2. So, of course, D means that the replication has been done before. After that, my cell is growing. After growing, septum formation and cell separation. Next question. This is a little bit of a question. If someone comes to it, he can do it. which media will be used if you want to remove a staphylococcus? I will use a manitol salt, acess

51:10 or a long string jensen media. देखो अगर हम इसमें मैनिटोल की बात करते हैं तो आंसर है मैनिटोल साल्ट क्योंकि यहां पर सेलेक्टिव मीडिया की तरह यूज होती है आपने टाइपस अपर मीडिया ऐसे पढ़ागा कि इसलेक्टिव क्या डिफरेंशल है तो यह सेलेक्टिव मीडिया के लिए क्योंकि I will talk about this SS agar. SS agar is for Salmonella and Sleginella. This agar is called in short form. I talk about this, which is for our

51:55 enterobacteria. It is basically gram positive. और लास्ट वन जो है हमारा कौन है लाउंस्टेंजेंसेंजेंसें मीडिया जो होता यह भी निया क्योंकि यह आपका माइको बैक्तिरियम क्यूबर क्लॉसिस के लिए देखने को मिलता है तो आंसर हो जाना था सिंपल टू नेक्स्ट आता है आपका जो मेले लिए कॉश्टिन ह Terminal centers are present with time to time size increases and in this body is produced. Immunology question

52:42 is not? Your organs are immune. So this is called SCQP03. Microbiology is now. So remember the antigen presentation, B cell response was shown there. So there is a role in your germinal center. Antigen is being trapped or a mutation? There is a production of antibodies. So the answer was 3. I have two questions. I have to tell you question number 31. Yes ma'am. 31, yes. Tell me which of the following form of DNA is produced with a DNA

53:28 sequence made up from alternating purine and pyrimidine nucleotide. Yes, tell me. Purine, Pyramidine, Purine, Pyramidine, Alternating Purine, Pyramidine, which is your place. And which DNA form is found in DNA? We told you a chart for a lot of times. We said that the questions come from here. There is also a question in zoo, in botany, in life science and in micro. So this chart is very important which you also understood in CPL. It will be possible, it will be possible, it will be possible. तो कौन सी form है बच्छा पाईटी जल्दी से बता हो कौन सी form को टिक करके आयो भाई A करके आयो B करके आयो या Z करके आयो भाई इसका अंसर हो का Z form यानि के B only Z form में धेखने के लिए मिलता है तो 1205 जो है

54:19 इसका अंसर हो जाएगा 2nd यानि के 4778 और एक और question मेरा यहाँ पर गया ह Question number 21, a question that I missed you. Here we go. Question number 21. What are the functions of peroxizomes? What are the functions of peroxizomes? Look, you get peroxidase. What does peroxidase do? What does hydrogen peroxide do? It is forming. So, if any substrate is present, what does it do? What does it do? What does it do? It will form hydrogen peroxide. अपना हाइड्रोजन दे दो और यह इस

55:06 तरीके से क्या बनवा दो हाइड्रोजन पर उक्साइड और सब्स्ट्रेट कर तो रिली पहले सब्स्ट्रेट के पास हाइड्रोजन ते तो रिड्यूस फोम में था हाइड्रोजन चलेगा यब ऑक्सिडाइज हो गया तो यहां पर हम सब्स्ट्रेट का ऑक्सिडेशन करते हैं कि हम उसके हाइड्रोजन चुडा लेते हैं और अल्टिमेटली क्या बन जाता है है तो त

55:58 क्या करेंगा hydrogen peroxide का breakdown करेंगा अगर catalyze mutated हो गया catalyze mutated हो गया तो हमारे hydrogen peroxide से OH के free radicals बनेगे और यह free radicals experience जाके क्या करते है बई यह free radicals जाके आपके DNA को damage करते है और DNA damage अगर आपका हो जाता है इस case में तो हमें Zell-Wagger syndrome नाम की बिमारी हो जाती है जिसमें 3 महिने में हमारी मौ ठीक है तो क्या catalyze जो होता है hydrogen peroxide को तोड़ता है जी बिल्कुल ए और भी तो सही है plants और fungi में fatty acid oxidation peroxizome में होता है yes मैंने ऐसे यद किया हुआ है P or P लेकिन aspirants अगर हम animals की बात करें तो animals के case

56:44 में fatty acid oxidation mitochondria में भी होता है और peroxizome में होता है yes सारे answer सही है a b c d यानिकि 3 answer हो गया question id 1172 is your answer is 3 a b c d 4 6 4 7 okay? the other question here is 36 question check let's check 35 left जो गरेक्ट आंसर इस और आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन

57:38 आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिकेशन आप्लिके� bands of separated particles appear औरें जब rotor rest में हैं, मतलब जब आपने उसे घुमा दिया, उसके last में जाकर आपको bands formation देखने को मिलते हैं, बिल्कुल सही बात है भई, यह आपको आखरी में देखने को मिलें, centrifuge जो tube है उसे आप gradient से fill करते हो, तभी तो नाम आए density gradient, जिसमें आप sucrose का, या फिर जैसे तो यह भी सही बात है। सेडिमेंटेशन और सेप्रेशन ऑफ दपार्टिकल्स अकर ड्यूरिंग दा सेंट्रिफ्यूगेशन यह सेडिमेंटेशन आता है और

58:26 आपका यहां पर पार्टिकल्स का सेप्रेशन होता है अपनी अपनी लेर में अपने पार्टिकल्स सेप्रेट आउ� The rotor is accelerating and moving the particles and the sample is reorienting and the gradient will show the gradient here. So what will our answer be? What will be option number 3? That means 4 of 4 options are correct. Let's go, there is a question here. In the dye hybrid cross. percentage is 20% which percentage is recombination? what is the distance? you know here is 1% which is equal to 1 cm

59:13 or 1 map unit? how much percentage is? 20% is equal to 20 cm or 20 map units? this will be the answer 20 अंसर येस, 3rd के अंदर 20 हमें अंसर दिया हुआ है, तो question ID 1200 का answer 3rd होगा, यालिके 4759 होगा, एक बर मैं आपको जो मेरे questions है, micro के वो करवा रेती हूँ, फिर Nikita मैं आपके साथ discussion जो है, वो कर लेंगी वही, question number 37 भी मेरा ही है, कह रहा है, which of the following is not an asexual method of reproduction in fungi, फंजाई के अंदर

1:00:00 we talk about sports. Whatever we talk about, this is all in respect of asexual reproduction and when you make gametes and fertilization, fusion, who comes into it? It comes into sexual. So we have asked a nod. What is the nod? What will happen? Give it NGIA. So 1, 2, 0, 4, 4, 7, 7, 3. So we have to check the answer from the answer. ग्रूप ट्रांस लोकेशन के बारे में पूछा हुआ है इन में से कौन से फीचर से ग्रूप ट्रांस लोकेशन के आपको करेक्ट बताना है ग्रूप ट्रांस लोकेशन का मतलब क्या होता है यह आपके

1:00:46 यहाँ पर सेल प्रेजेंट है और यह प्रेजेंट है आपकी सेल की मेंब चलो भई यहां पर आपके पास अगर आपको क्या करवान है आपको किसी मॉलीक्यूल का ट्रांसफर करवान है और आप यहां पर किसी सिस्टम को यूज कर रहे हो तो वह आपका बेसिकली ग्रूप ट्रांसलोकेशन के अंदर आता है जैसे कि आप यहां पर पिच्चर भी देख पर

1:01:35 चाहते हैं सब्सक्राइब आपको इसको कोई ना कोई क्या देना पड़ेगा कोई ना कोई मॉलीक्यूल देना पड़ेगा जिसकी वज़े से यह तुबारा मेंब्रेन को क्रोस ना कर पाए जैसे कि बाहर जो ग्लुकोस प्रेसेंट है यह सेल के अंदर आ रहा है लेकिन अब देते हैं क्योंकि इसके उपर phosphate के बाद माइनस वन चार्ज आ जाएगा और चार्ज वाली चीज़ें मेंब्रेन को simple diffusion के तुरू क्रोस नहीं कर सकती है तो generally हमारे पास यहां पर systems present होते हैं PTS, phosphotransferase enzyme systems, यह क्या करते हैं किसी molecule को जहां trap करना होता है, generally इनको phosphate दे देते हैं, phosphate देने की वज़े से

1:02:23 जो molecules है, वो cell के अंदर क्या रहते हैं, trap रहते हैं, तो यह group translocation को लेके question आया था, और group translocation जो है, यह हमारा primary active transport के अंदर आता है, इस और अगर ATP डारेक्ट खट जोता है तो वो किसके अंदर आता है? प्राइम रियक्टिव ट्रांसपोर्ट के अंदर आता है तो यहां पर अपना अशर चंक कर लेके हैं बहीं कहारा है यहां पर जो मॉलीक्यूल है उसको केमिकली मॉडिफाइड किया जाता है जब ट्रांसपोर्

1:03:10 we don't modify it now we modify it and we do phosphorylation we say the molecule is phosphorylated or completely it is the second reactive transport it is the example of primary active transport so our A and C is correct so we say the answer is 4771 what is 4771 okay let's go now I will give you my next question which is my इसा मच सोच ना बागी कोश्चन नहीं करवा रहे है वै निकिता मैं आम बागी कोश्चन करवाएंगी तुम्हारे निकिता मैं आम बागी कोश्चन करवाएंगी जो उनके हैं वै ठीक है मेरा यहां पर 45 कोश्चन है वै पोश्चन नमबर 45

1:04:05 ये अच्छा कोश्चन है ये मेटाबॉलीजम से कोश्चन आया है और ये कोश्चन अच्छा आया है देखो जन्रली या तो हमारी कैलकुलेशन में 38 अंसर आता है या हमारी कैलकुलेशन में 32 या फिर 30 अंसर ही आता है Our 38 answer is when we know the exact value of the exact value of the NADH. If we know that the exact value of the NADH is approximately 2 ATP and the exact answer is 1.5 ATP, then our answer fluctuates here. Now, what do we answer here? 210 EWS Micropology नीमात्री पर्टी 100% सेलेक्शन है 100% सेलेक्शन है भई

1:04:55 नहीं भई आठ अंसर आठ अंसर जो है वो गलप नहीं है लग रहे हैं तो प्रवाइब लग रहे हैं तो प्रवाइब लग रहे हैं तो प्रवाइब लग रहे हैं अब यह देखो कितना एक पीछ वह बनता है जब आप एक ग्लुकोस को ऑक्सिडाइज करते हो और शिदेटी फोस्पोराइलेशन से बताने हैं और सब्स्ट्रेट लेव and we get 2 NADH. Then our link reaction here. Pyruvate decarboxylation, matrix link reaction.

1:05:42 Then our crap cycle goes. If we talk about one round, we will talk about two rounds because there are two acidiles. In one round, we have 3 NADH. One has ATP or GTP and one has FADH. So, this will multiply by 2. calculation from here. What has it come from here? 6 has NADH, 2 has ATP present, 2 has FADH2 present. So this is what comes from our substrate level phosphorylation and this also comes from SLP. For SLP, 4 ATP is used to ATP आएंगे इस calculation से या 32 या 30

1:06:32 आएंगे 4 बन चुके हैं तो 38 में से 4 माइनस करना कितना आएगा 34 आएगा और यहां 32 में से 4 माइनस कर दो answer कितना आना चाहिए था 28 तो क्या तुम्हें यहां पर 28 अंसर दे रहा है 32 के साथ 4 का combination बन सकता है नहीं बन सकता तो elimination method से भी तुम answer निकाल तो हमारा अंसर यहां पर क्या आना

1:07:22 चाहिए भई हमारा अंसर एस्पिनेट्स यहां पर आपका सेक्ट आना चाहिए यह अभी SCQP03 चल रहा है और अगर आपको यहां पर 2026 के लिए preparation करनी है या आप यहां पर December 2025 के लिए preparation करना चाहते हैं तो आप Genome 2.0 जोइन कर सकते हैं इस particular number पर call करके ठीक है और बताइए बैए और कोई query किसी की Is there any

1:08:25 other query? Tell me, is there any query? 51 question मैं अपना और बता देती हूँ question no 51 इधर देखो कह रहे है Coenzymes and prosthetic groups are small non-protein molecules that participate in catalysis. What is the difference in them? Simple thing you know, the coenzymes are present, when they bind, they are very loose binding. How is it? Very loose binding. And if we bind with prosthetic groups, how is it tight? The biggest difference in prosthetic group and co-enzymes is the most

1:09:12 important thing. So, how do the binding of co-enzymes? It is very loose. What do you want to reply? BHU can be found. There are some chances of finding. And how do the prosthetic group bind? Tightly. That means the first answer will be right. NAD plus is the prosthetic group example or not. NAD plus is our co-enzymes example here. Which example is co-enzymes? अगरे कोश्चन की तरफ आगे भड़ते हैं भई कोश्चन नमबर 58 मेरा है अभी आपर 53 sorry

1:10:00 53 54 को शेयर और लाइक करेंगे सभी अस्पिरेंट्स सेशन को शेयर और लाइक करेंगे

1:10:50 but the person who is new is first time or who feels that my marks are not coming so much so that my exam is clear and where it is not going to be selected so you can use this combo offer. If you feel that my exam is good and my number can be selected इसी टाइम पर अपने December 2025 के लिए प्रेपरेशन कर सकते हैं नेट जो बैच है उसे खरीब सकते हैं और उसके साथ कॉम्बो बोलाए ना तो मतलब उसका गेट आपको इना पर फ्री मिलेगा तो आप यहां

1:11:40 पर अगें सीवीटी पीजी you will get a recording of the jam if someone wants to prepare for jam, get a batch of GatB and you will get free of these things you are getting here in 5200. If anyone thinks that my preparation will not have to boost me because I have not done the last time because I have been sitting there एक्जाम आने से दो तीन महीने पहले पढ़ना शुरू कर रहे हैं क्योंकि इस वार के questions वह आले नहीं है जो सोचा और अंसर टिक हो गया ऐसे question बहुत कम है वह

1:12:27 भी micro में आये जू में तो आपको यहां पर ऐसे धील नहीं देनी आप इसे preparation strong करनी है तो यह batch आपका पर present है किसी को What is your question? Vector is a vector which we see in antibiotic resistance genes. What are the present in the antibiotic resistance genes? What are the

1:13:13 answer for eyesight? What will be the answer for screening or selection? Whenever we study biotech, RDT, I always have said that there are selection markers. Which resistance genes are? यह इनहां पर selection markers है select करेंगे कि कौन से cells यहां पर हमारे और कौन से cells हमारे काम के नहीं है selection करने पर help करते हैं तो यह इसका काम है selection marker अगला आता है first cell जो यहां पर पौशता है किसी inflammation पर या basically बो सकते हो किसी injury site पर जो सबसे पहले पौशता है वो इन चारों में से कौन सा cell होता ह So,

1:14:02 the next question is which have ability to grow in very dry environment. It is dry, it is dry in desert area. What do you see? Desert, which we can say zero phyts. We have bacteria, bacteria tau, we also say it in plants. Zero phytic condition. Halophytes are very acidic and salty environment. In acidophiles are

1:14:49 acidic. Zero phyts are the ones that and we will see in the dry area. Zero fights was a very easy question. T cell receptor is a cytotoxic T lymphocyte. It is a T cell receptor. So, who will interact with it? If I give it any cell to it, तो यहां पर इसको अफ़ोर्स प्रेजेंट करेगा अगर यह Tc है तो हमने बोला था MHC 1 आएगा और प्रेजेंट किसको करेगा हमारे एंटीजन को तो तो तो यह

1:15:38 देखने को मिल रहा है हमें ठीके तो यह देख लो कौन सा एंट्रेक्ट कर रहा है वह तो यह वन के साथ इंट् CD8 के साथ यह क्यों interact करेगा क्योंकि वो तो इसका particle है इसका molecule है जो ऐसे interact करेगा CD8 करेगा T cell receptor CD8 से interact कर रहा है नहीं तो यह तो नहीं होगा This is a very easy question, bacterial growth curve which we have studied that it is land phase, low phase, stationary phase and decline. Now you can see which phase is in which there is no net increase or decrease. Tell the name of that phase. So here in death phase there is decrease. Then stationary phase is in which there are many

1:16:27 births and deaths. which is not increased for the reason. It will also be for the zoology and licenses. Next. If organism A possess 55% of G plus C content, one has 55% GC, the other 25% GC In their genome, what do you get to see the inference? Do you think that one can study the same as the other? Both are closely related or not? Closely

1:17:14 related, not as the percentage of the same This is the same thing that both are different. So, you can't call it the same thing. Both can belong to different text zones. So, you can give both of your answers. If someone has B put it, they will also be correct. So this answer is B and C. We know that both are unrelated because one is 55 and one is 25. So unrelated is for sure. C says that both are from Texas. This is also unrelated. So they have

1:18:00 both answered B and C. Next, the steps of PCR, the correct answer is B. If you want to ask them first, then you can remove this. After that, you will be able to use A. What will happen? The answer will be 3rd. Next question. If someone wants to do this, you can challenge them a little bit. Because they asked them to If you look at this question, there is 48 number question. Question IT, look at 1194. In this 1194, ask you who is responsible for doing mRNA in prokaryotes.

1:18:49 In prokaryotes, there is a normal RNA, polymase A, which is used to do, but who is given to you? U-karyotes. So if you want to challenge this question, you can do it. If anyone has clicked anything, you have to give them a number because these options are not correct here. If we see the rest of this, you can add 3 of this because if you look at the eukaryotes case, it is mRNA synthesis. Option number 3, RNA polymerase 2. Clear? Let's go. Next question. Yes, this is a great question. We follow the well-less rule. Tell the melting temperature. If there is a primer sequence, it is used in PCR. You can add the annealing temperature. इसके अंदर एक formula है जैसे 4

1:19:37 into G plus C content कितना है और 2 A plus C content कितना है बस यही देखना था और इसको calculate करके wellis rule हम कहते हैं इसे हमें लगाना है G plus C देख लो 1 2 3 4 5 6 7 8 9 10 11 तो यह 11 आ रहे हैं मतलब 44 इधर से आ रहे है A और D देख लो 1 2 3 4 5 6 7 So what will be the answer? Option number 8. So this is a very easy question. You can also answer such questions. Okay? Next question. arrange steps in the RNA synthesis, arrange in the toddler, which one is correct?

1:20:22 that the polymerase will be released, release of the sigma factor, recognition, yes, first of all, let's understand the promoter, the promoter will start, sigma factor will come, so this should be the first one, so C will come, this is the right thing, so C will come, after that, as you reach the elongation step, sigma factor will be different, so second, this will come, Second, this one, not D. So what will this answer be? Option number B. Next question. In this question, I think it has a little bit of a state. We will see the rest and then cut. Which factor is a very good answer.

1:21:13 बेल को यह नहीं पदा बाकी का लेकिन मुझे इसका पता है यह सबसे इन चारों में सबसे जादा बैक है क्योंकि यह आठीफिशियल कर रहा है लगवक 300 बेस पेर्स तक को किलो बेस पेर्स तक को यह अपने अंदर ले सकता है तो सबसे जादा ही सकता है तो सबसे एंड में आन You should answer D the last one. What do you think? Because if I have to arrange it, my back is the most important amount of carrying capacity. But the less than the plasmid

1:21:58 is the first one. You should have the option D. D has given option D, that first C will come, but there is a gut bird here, this is the number one, the smallest, bacteria of ours has given it to them. Gut bird has given D and A, they have given D and D, Cosmit, which is 35-45 kg base perl, put it on A, So this mistake is 4th number question option. So if anyone wants it, this can claim that they have been wrong in size. They have been wrong with their options. So

1:22:46 this is a little optional mistake. The other question is okay. In the option, there is a wrong question. But if you have most correct, then option number 4 is our answer. Okay? Next question. which number is now 52? Next, which number is most abundant protein? I think this is a repeat question in micro and at that time, it was simple rubisco, we said simple, we wrote it and wrote it in full form, so they wrote it here, rubisco is the most abundant protein on earth If you have to go ahead and do

1:23:37 it, then you will come back. Yes, I will be in 54. Yes ma'am. If you have asked so many times, the question comes from ecology and you have also asked to remember the interaction. Here, the question comes from here. If we talk about interaction, what is commensalism? It is plus zero. Competition is minus minus. Commensalism is minus zero. Parasitism is plus minus. Yes, let's go. It says that one population is better and the other is not affected. That means it is plus and zero. Plus zero means commensalism. What do you do? One, do you do third. One, third. I do two options from elimination. One is cut. Then, where one population drives food from the host. That means what relation is coming to you? Host or parasite. And you don't kill the host. So what do you call this

1:24:25 relationship? Paracitism. Who is killing it? Don't confuse it, it becomes a parasitoid. In the parasitoid, our parasite eventually what does host do? Kill it. So parasitism here. D has been given first. D has been given second. D has been given first. D has been given first. D has been given first. D has been given first. You have given second. Competition means that both of them are getting lost. Okay, competition means that it is the same. So B has been given fourth. And Amenzalism means that one is negative and one is unaffected. Minus zero. یہاں پر ہمارا انصر آگیا سیکنڈ ون بان ایٹ سیون کا انصر ہوگا فور سیون زیرو سیکس والا ٹھیک ہے چلو بھائی

1:25:11 آپ کا دا اچھا What is the function of impellers in a fermenter? What is the function of impellers in a fermenter? What is the function of impellers? You have to mix all the things. You have to mix oxygen and stir the medium. The answer is your fourth. But the third and fourth are all right. You have to increase your turbulence. You have to mix nutrients, mix oxygen, and stir the medium. So this is an overall function and an overall function of a part that we mix season when it is stirring. So here 3rd and 4th should be answered but the answer is only 4th but yes the answer is

1:26:01 correct. So if I think change correct or put it here then it can be added. 54, 1,1,93 NTN has 4732 here but these 2 There are two options, because there is a mixing of oxygen. After that, you have 59, 60, 61, 62, 64, 67. Let's see, I will give you my part, then I will end up with you. yes, during catabolism catabolism means cut, or breakdown, which is what is going on? my dear, breakdown is what is going on here. for this, for this, the fermenter is written in the book, it is written in the book that the

1:26:47 oxygen mix is going on, so you can use any book that has been given in the fermentation, you can put the topic in the reference. catabolism, when ATP is produced directly from intermediate, When you are breaking the substrate, there is a product from substrate and you have released ATP. What do you mean? It is called substrate-level phosphorylation. Where did you study? Glycolysis, and also in Grab cycle. You remember that when you did what you did here, you made pyruvate from PEP. So did you synthesize two ATP? पले substrate level phosphorylation का तो क्या इसको oxidative phosphorylation क्याते है नहीं

1:27:36 oxidative का मतलब क्या होता है हमारे जो NADH और FADH2 है यह जब अपना oxidation करते हैं यानि जब आप इनके electron लेते हो तो इनके electron लेते टाइनन को oxidize करवाते समय energy मिलती है उस energy से आप ATP बनवा रहे हो यानि कि oxidative phosphorylation एक indirect method है ATP बनाने का डा What is the most fake level phosphorization? I am just saying that the first question is only 4502. You have taken the question and you have to make sure that all the questions are just going to challenge. And I have told you this offer. If the score is good, then December 2025. Target the paper on the net. If the score is

1:28:22 not good, then you can give the CVT PG paper back in 2016. Let's start. Arrange the following intermediate on the basis of their synthesis in citric acid cycle. Crab cycle has been told in 1000 times. How many steps are there in the 8th step? Where are there? What is the first step? From oxalocity acid. This is a STQP03 micro paper. First of all, what do we give to oxaloacetic acid? Acetyl coenzyme A. And there is a synthesis here. Many children are telling me the answer. पुछा हुआ है synthesis की respect में तो तुम्हे

1:29:12 लगता है सबसे पहले तो oxaloacetic acid आ रहा है इसका synthesis नहीं हो रहा है इसको आप substrate की तरह यूज हो रहे हो सिंथेस तो सबसे बाद में होता है याद करो step number 8 क्या था? Malate से oxaloacetic acid बनाना तो synthesis तो तुम्हारा 8th step होता है तो तो तो तो तो तो त क्या बनता है citrate, तो यहां पर यह रहा citrate, citrate हमने यहां पर बना दिया, citrate के बाद क्या बनाते हो, isocitrate, isocitrate से क्या बनाते हो, alpha keto और alpha keto से क्या बनाते हो, alpha keto से तुम बनवाते हो, यहां पर succinyl coenzyme A, यही सारी बाते चलती है

1:30:00 न, तुम क्या बनवाते हो end में, अपना shallow acetic acid बना so you are wrong after a what is a called a called a called a called a called c called b called d called d called d called 1190 4718 what will happen then correct answer will be correct let's tell you 61 and 62 रहा हमारा 61 question सबसे जादा ozone को कोण deplete कर रहा है जिन्दगी बीट गई ये बात पढ़ने में वही ये जो chlorofluorocarbon होते हैं hydro chlorofluorocarbon होते हैं hydrofluorocarbon होते हैं जितने भी halogenated carbons होते हैं ये सारे के

1:30:49 सारे हमारे oxygen को deplete करते हैं यानि कि 1181 cancer होगे 4681 चलो अब ये question की तरफ human abio blood group genetics में त� CPL Genetics में तुम्हें करवाया था कि भाईया हमारे पास यहां पर H Antigen होता है इस तरीके से देख सकते हो हमारे पास H यानि कि O Antigen present होता है यहां पर हम क्या करते हैं अगर N-Acetyl Galactose Transparase ले आए तो टर्मिनल पोजीशन पर N-Acetyl Galactose Amine लग जाता है और बॉंड बनता है Alpha 1-3 वहीं Here the galactose is a alpha 1-3 bond and this is beta antigen. So

1:31:37 both have one extra. In comparison, each one is a monosecrate extra. Here we have N-acetyl galactose and here we have galactose. Let's see the options. ग्लाइकोसाइल ट्रांसफरेज एंजाइम इस रिस्पॉंसिबल यहां पर ग्लाइकोसाइल ट्रांसफरेज एंजाइम जो है वो क्या है वो आपको यहां पर रिस्पॉंसिबल है तो हमने पीछे कौन से एंजाइम पड़े है इधर देखो भाई क्या यह सारे के सारे हमारे क्य

1:32:23 We call it galactose which gets a substance. And we call it extra monosacryptus which we call it galactose which is connected to the X. All options are here. What should our answer be? Our answer is 3. Let's tell you about a 64 question. Yes, see this question. There is something else on Google. इसमें चैट जीपीटी पे जो अंसर आ रहा है वो कुछ और है रिसार्च पेपर में जो अंसर आ रही है वो कुछ और है वई ठीक है यह नौट जस्टीफाइड ऑप्शन्स हैं इस ऑप्शन्स आर नौट जस्टीफाइड एंटी एन ने डीडीटी दिया है वई The answer is DDT. But many of you have said DDT. If we talk about research paper, it has also

1:33:12 shown patent. They have shown patent. And we refer different resources to this. In the book, we don't have any information about it. So, if you look at research paper, it has shown patent. But the answer is DDT. Okay? Let's go. And last question, question number 67. Solutes in the environment change the availability of water molecules to microbes. This is our solution and this is our small microorganism. So what are solutes here, change our water. How much water is available, change it. So tell us how to measure the quantity.

1:34:00 Better measure water activity. प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्रेजर पर प्र

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